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Fofino
2 months ago
10

The table shows Mr. Winkler’s schedule for paying off his credit card balance. A 5-column table with 4 rows. Column 1 is labeled

Balance with entries 650 dollars, 556 dollars and 60 cents, 462 dollars and 8 cents, 366 dollars and 42 cents. Column 2 is labeled payment with entries 100 dollars, 100 dollars, 100 dollars, 100 dollars. Column 3 is labeled new balance with entries 550 dollars, 456 dollars and 60 cents, 362 dollars and 8 cents, 266 dollars and 42 cents. Column 4 is labeled rate with entries 0.012, 0.012, 0.012, 0.012. Column 5 is labeled interest with entries 6 dollars and 60 cents, 5 dollars and 48 cents, 4. dollars and 34 cents, 3 dollars and 20 cents. If he continues to make monthly payments of $100, and makes no new purchases, how many more payments will he have to make before the balance is zero?
Mathematics
2 answers:
Inessa [12.5K]2 months ago
8 0

Response:

3

Detailed breakdown:

I completed it using EDG 2020

Leona [12.6K]2 months ago
6 0

Response:

3

Detailed explanation:

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The manufacturer's suggested retail price (MSRP) for a particular car is $25,425, and it is expected to be
PIT_PIT [12445]

Response:

(a) The linear depreciation function relating to the car's value y after a few years t is given by:

y = 25,425 - 2,739 × t

(b) The projected worth of the car in 7 years amounts to $6,252.

(c) The depreciation is at a rate of $2,739 yearly.

Step-by-step explanation:

The manufacturer's suggested retail price (MSRP) for the vehicle is $25,425.

Its expected valuation in 5 years is $11,730.

(a) The linear depreciation formula is as follows:

Depreciation \ Per \ Year \ = \dfrac{Cost \ of \, Asset - Salvage \ Value}{Life \ of \, Asset \ in \ use}

Where;

Asset Cost = $25,425

Salvage Value = $11,730

Asset Lifespan = 5 years

From this, we obtain;

Depreciation \ Per \ Year \ = \dfrac{\$ 25,425 - \$11,730}{5} = \$2,739/year

Thus, the linear depreciation function can be expressed as:

y - 25,425 = -2,739×(t - 0)

y = -2,739·t + 0 + 25,425 = 25,425 -2,739·t

y = 25,425 - 2,739 × t

Where;

y = The estimated worth of the car after a specified duration

t = The years calculated for depreciation

(b) The value of the vehicle in 7 years can be calculated as below;

For t = 7, we find;

y = 25,425 -2,739·t = y = 25,425 -2,739 × 7 = $6,252

The expected car value after 7 years is $6,252.

(c) Depreciation \ Per \ Year \ = \dfrac{\$ 25,425 - \$11,730}{5} = \$2,739/year

The car depreciates at a yearly rate of $2,739.

3 0
3 months ago
What is the range of the function represented by the graph?
Svet_ta [12734]

The right answer is C. y> 1

4 0
3 months ago
Read 2 more answers
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