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Nimfa-mama
2 months ago
9

In the diagram below, Bonnie claims that ΔMLV ≅ ΔRLT.

Mathematics
1 answer:
Leona [12.6K]2 months ago
3 0
∠ M ≅ ∠ R: true

<span>VL ≅ LT: true 

</span><span>Δ MLV can be rotated around point L to correspond with Δ RLT.: false

</span><span>A sequence of rigid transformations can align Δ MLV with Δ RLT.: true </span>
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Sean is conducting an experiment with an isotope of a particular element that has a half life of 4 hours. He begins with a sampl
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Detailed explanation of the process:

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3 months ago
Below is a probability distribution for the number of failures in an elementary statistics course. X 0 1 2 3 4 P(X=x) 0.41 0.18
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Answer:

a) P(X=2)= 0.29

b) P(X<2)= 0.59

c) P(X≤2)= 0.88

d) P(X>2)= 0.12

e) P(X=1 or X=4)= 0.24

f) P(1≤X≤4)= 0.59

Step-by-step explanation:

a) To find P(X=2), we calculate: P(X=2)= 1 - P(X=0) - P(X=1) - P(X=3) - P(X=4) which equals 1 - 0.41 - 0.18 - 0.06 - 0.06, resulting in 0.29

b) For P(X<2), we sum P(X=0) and P(X=1): 0.41 + 0.18 yields 0.59

c) To obtain P(X≤2), we add P(X=0), P(X=1), and P(X=2): 0.41 + 0.18 + 0.29 equals 0.88

d) To calculate P(X>2), we find P(X=3) + P(X=4): 0.06 + 0.06 gives us 0.12

e) For P(X=1 or X=4), we use the union of probabilities: P(X=1) + P(X=4) which is 0.18 + 0.06, resulting in 0.24

f) P(1≤X≤4) is found by adding P(X=1), P(X=2), P(X=3), and P(X=4): 0.18 + 0.29 + 0.06 + 0.06 results in 0.59

3 0
2 months ago
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3 months ago
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There is a safety fence around a circular pool with a gate. The gate is 150 cm wide. What is the length of the fence not includi
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Response:

The fence's length is expressed as 6.28x - 150 cm.

Detailed Breakdown:

Assuming the circular pool has a radius (r) of x cm.

As the pool is circular, its circumference represents the length of the fence. Additionally, subtracting the 150 cm for the gate gives us the actual length of the fence.

Length of fence = Circumference of pool – gate's width.

Length of fence = 2 π r – 150

Length of fence = 2 × 3.14 × x – 150

Therefore, the fence length is 6.28x – 150 cm.

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3 months ago
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