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stellarik
1 month ago
8

Sean is conducting an experiment with an isotope of a particular element that has a half life of 4 hours. He begins with a sampl

e of the isotope with a mass of 92 grams. He then measures the mass of the object every hour. What is the approximate mass of the sample after 20 hours. Choices are: A: 2.875 B:2,944 C:1.4375 D:0.0313
Mathematics
1 answer:
zzz [12.3K]1 month ago
5 0

Response:

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Detailed explanation of the process:

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Mario walked at a rate of 2/3 miles every 10 minutes what is his unit rate every mile per hour
AnnZ [12381]

Mario has a unit rate of 900 miles/hour.

Explanation:

It is given that Mario travels at a rate of 2/3 miles every 10 minutes.

We use the relation between speed, time, and distance, described by

\text{Speed}= \frac{\text{Distance}}{\text{Time}}

We have,

Distance = \frac{2}{3} \text{ miles}

Time = 10 minutes

By substituting these values into the preceding formula, we get

\text{Speed} = \frac{2/3}{10}\\\\ \text{Speed} =\frac{2}{10\cdot 3}\\\\ \text{Speed} =[tex]\frac{1}{15} \text{ miles/min}[/tex]

To express the unit rate in miles per hour, we must multiply by 60.

Thus, the resulting unit rate is

\frac{1}{15} \times 60\\ = 4 \text{ miles/hour}

5 0
21 day ago
Tom started an entertainment company. The net value of the company (in thousands of dollars) ttt months after its creation is mo
zzz [12365]
Step-by-step explanation: The entertainment company’s net value after t months can be expressed by the equation; v(t) = 4t² - 24t - 28. To factor this expression, we need to simplify the equation: v(t) = 4t² - 24t - 28, dividing everything by 4 yields: v(t) = t² - 6t - 7, v(t) = t² - 7t + t - 7, v(t) = t(t-7) + 1(t-7), v(t) = (t+1)(t-7). Thus, the function in factored form is v(t) = (t+1)(t-7). To find when the company hits its lowest value, substitute v(t) = 0 into the factored expression: v(t) = (t+1)(t-7). Setting equal to zero provides: (t+1)(t-7) = 0, leading to t + 1 = 0 and t - 7 = 0; thus, t = -1 and t = 7. Since time cannot be negative, therefore, t equals 7 months. This indicates that after 7 months, the company will reach its minimal net value.
8 0
12 days ago
The measure of central angle QRS is StartFraction 8 pi Over 9 EndFraction radians. What is the area of the shaded sector? 36Pi u
babunello [11817]

The illustration is omitted. Please see the attachment below.

Answer:

The area of the shaded sector is 144π square units.

Step-by-step breakdown:

Given:

The central angle for the sector is, \theta=\frac{8\pi}{9}\ rad

The circle's radius is, R=18\ units

The area of a sector with radius 'R' and angle \theta can be determined with:

A=\frac{1}{2}R^2\theta

Substituting \theta=\frac{8\pi}{9},R=18 gives

A=\frac{1}{2}\times (18)^2\times \frac{8\pi}{9}\\\\A=(\frac{324\times 4}{9})\pi\\\\A=(36\times 4)\pi\\\\A=144\pi\ units^2

Thus, the area of the shaded sector calculates to 144π square units.

5 0
1 month ago
Read 2 more answers
Mia paints interior walls at a rate of 12 m^2/h. At what rate does she paint in cm^2/min?
Inessa [12570]
12 m^2/h to cm^2/min

12 m^2/h × 1 h/60 min = 0.2 m^2/min

0.2 m^2/min × 10000 cm^2/1 m^2 = 2000 cm^2/min

2000 cm^2/min
6 0
1 month ago
Read 2 more answers
A customer/member owes $10.51 and pays $50.00 in cash. The change due is $39.49. Provide the amount owed using the smallest numb
Leona [12618]

The total number of bills and coins is 14.

Step-by-step explanation:

To minimize the count of bills and coins, start with the largest denominations that fit within the amount.

The change due is $39.49.

Start with:

-$20 bill (largest under $39.49)

Remaining: $19.49

-$10 bill (largest under $19.49)

Remaining: $9.49

-$5 bill (largest under $9.49)

Remaining: $4.49

Then:

4 × $1 bills (to cover $4.49)

Remaining: $0.49

-$0.25 coin (quarter)

Remaining: $0.24

2 × $0.10 coins (dimes)

Remaining: $0.04

4 × $0.01 coins (pennies)

The final composition includes:

1 twenty-dollar bill

1 ten-dollar bill

1 five-dollar bill

4 one-dollar bills

1 quarter

2 dimes

4 pennies

Totaling 14 pieces.

5 0
2 months ago
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