Answer:
a. A relative-frequency distribution relates to a variable just as a _____probability_____ distribution relates to a random variable. b. A relative-frequency histogram pertains to a variable similarly to how a _____probability_____ histogram pertains to a random variable.
Step-by-step explanation:
Probability, a mathematical concept, involves numerical assessments of how likely a certain event may occur, indicating the validity of its occurrence. The range for the probability of any event is typically between 0 and 1,
with 0 signifying impossibility and 1 indicating certainty of occurrence.
Answer:
Step-by-step explanation:
Overall students=50
35 -> j.
25 -> r.
16-> j.+r.
35-16=19 students joined j.
25-16=9 joined r.
50-19+9
50-28=22
The answer is 22
It would be nice if you could give me the brainliest rating. Best of luck!
Answer:
Contained within.
Step-by-step explanation:
The accurate answer to the question posed is "contained within." This is because it was derived directly from the original text without requiring additional information, analysis, or interpretation in the new document.
Determining the answer here is quite straightforward. Ella has a total of $2.16, and we need to ascertain the cost per piece of gum.
It is known that if the gum cost one cent less, she would have acquired three more pieces.
Currently, with 8 pieces priced at 27 cents each, a reduced price would allow her to have 8.64 pieces. This outcome, even after rounding, is incorrect as it does not yield 11.
For 9 pieces at 24 cents each, a cheaper price would mean she could have 9.39 pieces, which still does not round to 12, indicating it's incorrect.
At 16 pieces costing 13.5 cents each, at one cent less, she would acquire 17.28 pieces, which also confirms it's wrong because rounding does not yield 19.
When purchasing 24 pieces at 9 cents each, with the cheaper price, she could buy 27 pieces, which is valid since 27-24 equals 3.
Therefore, the correct answer is D) 24
Answer: 26.3 mm
Step-by-step explanation:
The two-standard deviations rule for outliers states that any value lying outside two standard deviations from the average is considered an outlier.
Given that the Mean is 23.5 millimeters (mm) and the standard deviation is 1.4 mm
The maximum thickness that should be reviewed = mean + 2 (standard deviation)
= 23.5 + 2(1.4)
= 23.5 + 2.8
= 26.3 mm
therefore, the maximum thickness warranting machine configuration review by the statistician = 26.3 mm.
