The manager of an industrial plant is planning to buy a new machine. For each day’s operation, the number of repairs X, that the

Answer:

Refer to the explanation provided

Detailed explanation:

Variable Name R2 value Adj R2 value

Earnings Per Share 0.086535 0.077214

Earnings Per Share,

Dividends Per Share 0.103976 0.085501

Earnings Per Share,

Dividends Per Share,

Average Yield 0.180303 0.154687

Earnings Per Share,

Dividends Per Share,

Average Yield,

Return on Equity 0.183215 0.148824

Earnings Per Share,

Dividends Per Share,

Average Yield,

Return on Equity,

Total Assets 0.184669 0.141301

Earnings Per Share,

Dividends Per Share,

Average Yield,

Return on Equity,

Total Assets,

Total Revenues 0.187297 0.134865

Answer:

i) A total of 40320 different arrangements

ii) For the initial 3 spots, there are 336 different combinations.

Step-by-step explanation:

Given: The total finalists = 8

The count of boys = 3

The count of girls = 5

To determine the number of sample point in the sample space S for possible arrangements, we calculate the factorial of 8!

The number of possible arrangements equals 8!

= 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

= 40320

ii) Among the 8 finalists, we must select the first 3 spots. The sequence matters, hence we utilize permutation.

nPr =

Here n = 8 and r = 3

Substituting n = 8 and r = 3 into the formula, we arrive at

8P3 =

=

= 6.7.8

= 336

Thus, there are 336 different arrangements for the first 3 spots.