90kg of sand was divided into 3 bags, constituting a total of 2+3+7=12 sections.
90kg/12=7.5kg
The smaller bag comprises 2 sections, hence it weighs 7.5kg*2=15kg
The medium-sized bag consists of 3 sections, leading to a total weight of 7.5kg*3=22.5kg
The larger bag encompasses 7 sections, resulting in a weight of 7.5kg*7=52.5kg
Thus, the ratio 2:3:7 translates to 15kg:22.5kg:52.5kg
Verifying, 15kg+22.5kg+52.5kg equals 90kg
C. No, because at least one of the sample sizes exceeds 10 percent of the population.
To find a122 in the sequence beginning with 5, 8, 11, we recognize this series is arithmetic.
No. 16.454 contains an extra digit at the end. If that final 4 were a 0, the two numbers would be equal.
Answer:
The mean decreases, while the median stays unchanged.
Step-by-step explanation:
A box plot is constructed from the quartiles of the data distribution, incorporating the maximum and minimum values. From this, one can determine the range, median, and interquartile range.
In this scenario, the median maintains its value at $9.5 per hour. The median is represented by the middle line in the box, which remains constant.
Conversely, the range of this data set shrinks from 7 to 3.
Moreover, the mean must decrease because values greater than $11 are no longer represented in the second box plot. The mean is a measure sensitive to such alterations.
Conclusively, the correct finding is The mean decreases, while the median remains unchanged.