This is the solution:
(3m^-2 n)^-3 / 6mn^-2
For the first step: apply the power distribution3^-3 m^-2*-3 n^-3 / 6mn^-2
In the second step: utilize the product and quotient rulesm^6 n^2/ 3^3 *6*m*n^3
Lastly, simplify the expressionm^5/162n
The conclusive answer is m^5/162n
Hope this aids you.:)
The provided values are
$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155
To start, we will arrange these in ascending order
resulting in
$60 $85 $95 $105 $120 $145 $155 $175 $190 $215 $235 $240 $260 $285 $315
The total count is 15
the position of 105 is 4
Now, we can calculate the percentile
Thus, the percentile for the bid of $105 is 26.667%...........Response
Answer:
x = -4/45
Step-by-step breakdown:
180x=2(30÷3)+17-5•11+2÷1
We first need to simplify the right side. The initial step involves the parentheses
180x=2(10)+17-5•11+2÷1
Next, we multiply and divide, proceeding from left to right after the equals sign.
180x=20+17-5•11+2÷1
180x=20+17-55+2÷1
180x=20+17-55+2
Next, we add and subtract, moving from left to right in relation to the equals sign.
180x=37-55+2
180x =-18+2
180x = -16
Then divide each side by 180
180x/180 = -16/180
x = -4/45
