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Oduvanchick
3 months ago
8

Kenji packed an exercise ball into a cylindrical package. The inflatable exercise ball is made out of vinyl. How much vinyl was

used to make the exercise ball? Express your answer in terms of pi.
Mathematics
1 answer:
Svet_ta [12.7K]3 months ago
8 0
An exercise ball, commonly referred to as a yoga ball, is a spherical object made from soft elastic material with a diameter ranging from approximately 35 to 85 centimeters (14 to 34 inches), inflated with air. The air pressure can be adjusted by inserting or removing a valve stem. It is frequently utilized in physical rehabilitation, sports training, and physical exercise. Additionally, it serves purposes in strength training. Often termed a Swiss ball, it is also recognized by various titles such as balance ball, therapy ball, fitness ball, gym ball, Pilates ball, stability ball, and others.
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Use the scale and map measurements to find the actual distance from New Wilmington to Sharon through Mercer. What is the actual
Inessa [12570]
Your response is C!

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8 0
2 months ago
Read 2 more answers
The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
Leona [12618]

Response:

a

    f'(t) is negative

b

 The unit is degC/min

c

At 35 minutes since the coffee was placed on the counter, the temperature is 68, and it will drop by approximately 0.75 in the next 30 seconds.

Detailed explanation:

According to the question, we are informed that

   The temperature of a cup of coffee on a counter is represented by the equation

         H= f(t)

where t indicates the time in minutes since the coffee was set on the counter.

In general, f(t)' denotes the derivative of f(t), indicating the change in temperature over time for the coffee

As the coffee rests on the counter, its temperature tends to decrease after a few minutes; thus, f(t)' is negative.

The temperature is measured in degrees Celsius while time is expressed in minutes.

Therefore, the change in temperature with respect to time, f(35)', will be given in degrees Celsius per minute (i.e., degC/min).

The question states that

        |f(35)'| = 1.5

which means the rate of temperature change after 35 minutes is 1.5.

And

         |f(35)| = 68

indicating that the coffee's temperature after 35 minutes is 67 degrees Celsius.

Subsequently, after another t= 30 seconds = \frac{30}{60}= 0.5 \ minutes the rate at which the coffee's temperature changes is

          R = |f(35)'| * t

=>        R = 1.5 * 0.5

=>        R = 0.75    

Thus

At 35 minutes since the coffee was placed on the counter, its temperature is 68 and will drop by roughly 0.75 in the next 30 seconds.

     

5 0
3 months ago
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