This is a cross-sectional view of candy bar ABC. A candy company wants to create a cylindrical container for candy bar ABC so th
at it is circumscribed about the candy bar. If segment AD = 3 cm, what is the smallest diameter of wrapper that will fit the candy bar? a.3
b.4
c.5
d.6
The answer is d. 6cm. Step-by-step explanation: The shapes form a right triangle. When circumscribed within a circle, the hypotenuse corresponds to the diameter. To determine the diameter, observe line AC as the hypotenuse. The two segments, AD and DC, are equal, evidenced by the single and double hash marks. Since point E bisects AE and EB congruently, point F also bisects BF and FC equally. Thus, we find that AD equals 3cm, making DC also 3cm. Combined, AC, the hypotenuse, measures 6cm. Hence, the minimum diameter of the wrapper that can accommodate the candy bar is 6cm.
The cake board’s circumference measures 35π cm. Initially, noting the cake's diameter of 30 cm, the board's diameter is established as an additional 5 cm, leading to circumference determination by applying the formula, yielding 35π cm.
