Find the missing probability. P(A)=15,P(A∪B)=1225,P(A∩B)=7100 ,P(B)=?

Answer:

p(B) = 8310

Detailed explanation:

We will apply the addition rule of probability for two events to address this question. According to the formula for two events A and B;

p(A∪B) = p(A)+p(B) - p(A∩B) where;

A∪B signifies the union of both sets A and B.

A∩B designates the intersection of the two sets A and B.

Given parameters

P(A)=15

P(A∪B)=1225

P(A∩B)=7100

Goal

To find the probability of event B, represented as P(B).

Using the above expression, we can calculate p(B); thus:

p(A∪B) = p(A)+p(B) - p(A∩B)

1225 = 15 + p(B) - 7100

Therefore, p(B) = 1225 - 15 + 7100

p(B) = 8310

Therefore, the missing probability p(B) is 8310.