A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obt

1,107 cc The scanning consists of 10 intervals: [0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15) To estimate the volume using the Midpoint Rule, n should be set to 10. Given that we will use n=5, we will split the range [0,15] into five intervals of lengths 3 each: [0,3], [3,6], [6,9], [9,12], [12,15] and calculate their midpoints: 1.5, 4.5, 7.5, 10.5, and 13.5. Next, we will determine the volume V from the five cylinders, where each has a height h=3 and the base area A corresponds to the calculated midpoints' intervals: Cylinder 1 Midpoint=1.5, corresponding to the 2nd interval A = 18, V= height * area of the base = 18*3 = 54 cc Cylinder 2 Midpoint=4.5, corresponding to the 4th interval A = 78, V= height * area of the base = 78*3 = 234 cc Cylinder 3 Midpoint=7.5, corresponding to the 6th interval A = 106, V= height * area of the base = 106*3 = 318 cc Cylinder 4 Midpoint=10.5, corresponding to the 8th interval A = 129, V= height * area of the base = 129*3 = 387 cc Cylinder 5 Midpoint=13.5, corresponding to the 10th interval A = 38, V= height * area of the base = 38*3 = 114 cc Thus, the estimated volume is 54 + 234 + 318 + 387 + 114 = 1,107