A CAT scan produces equally spaced cross-sectional views of a human organ that provide information about the organ otherwise obt

Answer:

- 128 Superscript StartFraction 3 Over x EndFraction

- (4RootIndex 3 StartRoot 2 EndRoot)x

- (4 (2 Superscript one-third Baseline) ) Superscript x

Step-by-step explanation:

Considerando la ecuación dada

De acuerdo con una de las leyes de índices,

Aplicando esta ley a la pregunta;

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

Response: The accurate statements include:-

There are nearly equal quantities of points located above and below the x-axis.

The points are distributed haphazardly without a distinct pattern.

The total number of points matches that of the scatter plot.

Explanation:

• A residual plot illustrates residuals on the vertical axis against the independent variable on the horizontal axis.

Consequently, the count of points is on par with the scatter plot, and roughly the same amount of points exist above and below the x-axis.

Given the random distribution of the points throughout the plot, it signifies there is no correlation, therefore, the points are scattered randomly without a clear arrangement.

Réponse:

Le domaine est l'ensemble des nombres réels

y ≤ 16

Explication étape par étape:

Le domaine est l'ensemble des valeurs x que le graphe couvre. Il n'y a aucune restriction sur les valeurs x. Le domaine est l'ensemble des nombres réels.

La plage est l'ensemble des valeurs y que le graphe couvre. Les valeurs y atteignent au maximum 16 au sommet de la parabole. Ainsi, la plage est y ≤ 16.

Answer:

The ratio   corresponds to the tangent of ∠I.

Step-by-step explanation:

Let’s revisit the trigonometric ratios:

• sin Ф =  
• cos Ф =  
• tan Ф =  

For triangle HIJ

∵ m∠J = 90°

- The hypotenuse is the side opposite the right angle.

So, HI is the hypotenuse.

∵ HJ = 3 units

∵ IH = 5 units

- We’ll apply the Pythagorean Theorem to solve for HJ.

∵ (HJ)² + (IJ)² = (IH)²

∴ 3² + (IJ)² = 5²

∴ 9 + (IJ)² = 25

- Subtract 9 from both sides.

∴ (IJ)² = 16

- Taking the square root on both sides gives:

∴ IJ = 4 units

To determine the tangent of ∠I, identify the sides that are opposite and adjacent to it.

∵ HJ is opposite to ∠I

∵ IJ is adjacent to ∠I

- Utilizing the rule of tan above:

∴ tan(∠I) =

∴ tan(∠I) =

The ratio indicates the tangent of ∠I.