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gregori
3 days ago
7

A tennis ball is tossed into the air. The height, h(t), in feet, of the tennis ball is a function of time, t, in seconds, as sho

wn in the table below.
t h(t)
0 0
0.5 20
1 32
1.5 36
2 32
2.5 20
3 0
Which statement provides a correct interpretation of the average rate of change of this function from t=1.5 to t=3?
A
The average rate of change is 24, which means that the tennis ball was rising at an average speed of 24 ft/sec.

B
The average rate of change is 24, which means that the tennis ball was falling at an average speed of 24 ft/sec.

C
The average rate of change is −24, which means that the tennis ball was rising at an average speed of 24 ft/sec.

D
The average rate of change is −24, which means that the tennis ball was falling at an average speed of 24 ft/sec.
Mathematics
2 answers:
lawyer [9.2K]3 days ago
5 0
I am hesitant to provide a definite answer since I'm not completely certain, but it's clear you can discard options C and D right away since the rate of change cannot be negative. Between options A and B, I would lean towards option B. I would have asked you to consider me the brainliest if I were correct, but I suspect this is for the IA4, where you're unable to check your grade... haha. Apologies, but I hope this assists you in some way!
lawyer [9.2K]3 days ago
4 0
I believe the correct answer is A.
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1 month ago
Read 2 more answers
Carmen is going to roll an 8-sided die 200 times. She predicts that she will roll a multiple of 4 twenty-five times. Based on th
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Answer:

Carmen's estimate is too low, since rolling 200 times \frac{1}{4} results in a total of 50.

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The sample space is Ω = {1,2,3,4,5,6,7,8}

For the event A: "Rolling an 8-sided die to get a multiple of 4"

The probability for event A is P(A)=\frac{2}{8}=\frac{1}{4}

This is because there are two multiples of 4 (4 and 8) out of a total of eight numbers (1 through 8).

Next, considering the random variable X: "Total count of multiples of 4 if she rolls an 8-sided die 200 times"

X can be described as following a Binomial distribution.

X ~ Bi (n,p)

X ~ Bi (200,\frac{1}{4})

Where n is the number of rolls and p is the probability of success, defined as rolling a multiple of 4.

The mean for this variable is

E(X)=np=200.\frac{1}{4}=50

Thus, we conclude that Carmen's prediction is low, as rolling 200 times \frac{1}{4} yields 50.

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