Consider the following differential equation. (A computer algebra system is recommended.) (1 + t2)y' + 4ty = (1 + t2)−2 (a) Draw

Response:

0.0000

Unusual

To explain step-by-step:

A tobacco company asserts that the nicotine content in its cigarettes behaves as a random variable with a mean of 2.2 mg and a standard deviation of.3 mg.

This means the population parameters are

The likelihood that the sample average would equal or exceed 3.1

equals 0.0000

The options you provided are unclear to me, so I will respond in general terms: to determine if a point (ordered pair) lies on a line, you need to substitute the x-value from that pair into the line's equation and check if the resulting y-value matches the y-value of the ordered pair. For example, if your line is y = 4/3x + 1/3, we can check if (0, 0) and (2, 3) fit this line. We find that y = 4/3·0 + 1/3 gives us 1/3, which does not equal 0, indicating (0, 0) is not on the line. For (2, 3), substituting yields y = 4/3·2 + 1/3 = 3, meaning (2, 3) is on the line.

The bathtub's depth measures 18 inches

It takes 2 minutes to fill 3 inches of the bathtub

Subsequently

The remaining depth needed for filling with water = (18-3) inches

                                                                        = 15 inches

The time needed to fill the remaining 15 inches of the bathtub = (15*2)/3 minutes

                                                                      = 30/3 minutes

                                                                      = 10 minutes

Therefore, John is right in believing that it will require an additional 10 minutes to fill the tub to the brim at the same rate.

Hope this clarifies things!

Respuesta:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Explicación paso a paso:

La probabilidad (P) de encontrar la partícula está dada por:

 

    (1)

La solución de la integral de la ecuación (1) es:

 

(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:

   

(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:

 

(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:

   

(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:

(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:

Espero que te ayude.

To find the height equation for the soccer ball's trajectory, we start with the acceleration due to gravity of g=9.81 m/s². Converting this gives us approximately 32.18 ft/s², rounded to 32 ft/s². The height formula is h = -g/2 * t² + vt + h0. Setting t=0 and h=0, we deduce that h0=0. Thus h=-16t² + vt applies. Given that the ball reaches 50 ft in 2.5 s, it reaches 25 ft in 1.25 s. Now, using 25=-16(1.25)² + v(1.25), we find velocity v=50/1.25, which simplifies to 40. Therefore, the height equation is h = -16t² + 40t.