To determine the average net force, we can calculate acceleration using:
x = 0.5*a*t^2
v = a*t
where x=3.6m and v=185 m/s.
Thus,
t=v/a and therefore x = 0.5*a*(v/a)^2 = 0.5 * (v^2)/a
which gives us a= (0.5*v^2)/x
Since we have the known values of v and x, we can compute a by substituting these numbers.
The average net force is then given as:
F = m*a,
with m=7.5kg.
Response:
The horizontal span of Sosa is 276.526 ft or 84.28 meters.
Explanation:
As illustrated in the diagram, let point O denote Sosa's starting position. She travels 361 ft at a 50-degree angle relative to the horizontal.
sin 50 = 
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meters
The horizontal distance of Sosa is 276.526 ft or 84.28 meters.
If the products have three nitrogen atoms, the reactants must have had the same quantity, as mass is conserved in a chemical reaction.
This is due to the fact that below 4°c, water behaves differently than other substances and decreases in density as its temperature drops further.
