Suppose Sammy Sosa hits a home run which travels 361. ft (110. m). Leaving the bat at 50 degrees above the horizontal, how high
did it travel?
1 answer:
Response:
The horizontal span of Sosa is 276.526 ft or 84.28 meters.
Explanation:
As illustrated in the diagram, let point O denote Sosa's starting position. She travels 361 ft at a 50-degree angle relative to the horizontal.
sin 50 =
0.7660 = h / 361
h = 276.526 ft
h = 84.28 meters
The horizontal distance of Sosa is 276.526 ft or 84.28 meters.
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Answer:
Explanation:
The measurement of pressure is indicated as where p denotes the pressure,
signifies density, and h represents height
Given values include pressure , gravity's acceleration
, and height =1.163 m
Answer:
The required energy remains identical in both scenarios since the specific heat capacity (Cp) does not change with varying pressure.
Explanation:
Given;
initial temperature, t₁ = 50 °C
final temperature, t₂ = 80 °C
Temperature change, ΔT = 80 °C - 50 °C = 30 °C
Pressure for scenario one = 1 atm
Pressure for scenario two = 3 atm
The energy needed in both scenarios is expressed as;
Where;
Cp denotes specific heat capacity, which only varies with temperature and remains unaffected by pressure.
Hence, the energy required remains the same for both scenarios since specific heat capacity (Cp) is pressure-independent.