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kvv77
3 months ago
15

Two identical objects are moving directly toward one another at the same speed v. ~v −~v m m What is the total kinetic energy of

the system of the two objects?
Physics
2 answers:
Maru [3.3K]3 months ago
7 0

Answer:

mv^2

Explanation:

Let m represent the mass of each object and v denote its velocity; the kinetic energy for one object can be expressed as

K_1 = \frac{1}{2}mv^2

The kinetic energy is determined solely by speed and not by velocity's direction. Consequently, the second object's kinetic energy will be identical:

K_2 = \frac{1}{2}mv^2

Thus, the total kinetic energy can be determined as

K=K_1 +K_2 = \frac{1}{2}mv^2+\frac{1}{2}mv^2=mv^2

inna [3.1K]3 months ago
5 0
<span>Answer: The correct response is simply sum the two kinetic energies: E = (1/2)mv^2 + (1/2)mv^2</span>
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The well-known equation... E = m c²... does not address the origin of the mass involved.

Converting 1 kg of any mass entirely into energy generates

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E = (1 kg) · (c²) = (1 kg) · (299,792,458 m/s)²

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3 months ago
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ValentinkaMS [3465]

Answer:

a. β = 8.23 K

b. β = 28.815 K

Explanation:

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β = TH / (TH - TC)

a.

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