Ask question

Ask question

All categories

2 months ago

14

James thinks of two numbers. He says "The Highest Common Factor (HCF) of my two numbers is 3 The Lowest Common Multiple (LCM) of

my two numbers is 45" Write down two numbers that James could be thinking of.

1 answer:

PIT_PIT [12.4K]2 months ago

5 0

The pairs that have an HCF of 3 and an LCM of 45 are (3,45) and (15,9).

You might be interested in

A machine can stamp 40 envelopes in 8 mins. How many of these machines working simultaneously are required or needed to stamp 12

lawyer [12517]

Answer:

24 minutes

Step-by-step explanation:

Let y represent the rate of 120 envelopes per minute.

40/8 = 120/y

40y = 8 * 120

40y = 960

y = 960/40

= 24 minutes

3 0

2 months ago

Read 2 more answers

An experiment was conducted to record the jumping distances of paper frogs made from construction paper. Based on the sample, th

tester [12383]

Answer:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

Step-by-step explanation:

Notation

$\bar X$ is the sample mean

$\mu$ indicates the population mean (the variable of interest)

s signifies the sample standard deviation

n denotes the sample size

Solution to the problem

The mean's confidence interval is derived from the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In this instance, the 9% confidence interval corresponds to:

$8.8104 \leq \mu \leq 11.1248$

We can determine the mean using the following:

$\bar X = \frac{8.8104 +11.1248}{2}= 9.9676$

Additionally, the margin of error can be calculated as:

$ME= \frac{11.1248- 8.8104}{2}= 1.1572$

The margin of error for this situation is expressed as:

$ME = t_{\alpha/2}\frac{s}{\sqrt{n}} = t_{\alpha/2} SE$

Next, we find the standard error:

$SE = \frac{ME}{t_{\alpha/2}}$

The critical value for a 95% confidence interval using a normal standard distribution is roughly 1.96, and substituting gives us:

$SE = \frac{1.1572}{1.96}= 0.5904$

For the 98% confidence interval, the significance corresponds to $\alpha=1-0.98= 0.02$ and $\alpha/2 = 0.01$ with a critical value of 2.326, yielding a confidence interval of:

$9.9676 - 2.326*0.5904 =8.594$

$9.9676 + 2.326*0.5904 =11.341$

8 0

2 months ago

7. During a person's commute to school, she spends 10 minutes driving 30 miles per hour (mph) and 5 minutes stopped at red light

Inessa [12570]

Answer:

5 miles in total

Step-by-step explanation:

Given:

Time spent driving = 10 min = 10 / 60 = 1/6 hour

Duration of stop = 5 min

Driving speed = 30 miles per hour

Find:

Complete distance

Computation:

Distance traveled = Speed × time

Distance = 30 × (1/6)

Total distance = 5 miles

5 0

3 months ago

If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t

lawyer [12517]

The options you provided are unclear to me, so I will respond in general terms: to determine if a point (ordered pair) lies on a line, you need to substitute the x-value from that pair into the line's equation and check if the resulting y-value matches the y-value of the ordered pair. For example, if your line is y = 4/3x + 1/3, we can check if (0, 0) and (2, 3) fit this line. We find that y = 4/3·0 + 1/3 gives us 1/3, which does not equal 0, indicating (0, 0) is not on the line. For (2, 3), substituting yields y = 4/3·2 + 1/3 = 3, meaning (2, 3) is on the line.

6 0

2 months ago

Read 2 more answers

Mara ran 3km north and then 4km east. She will finish her run by running directly home. What was the total distance of her run?

tester [12383]

To find the hypotenuse of a right triangle with sides measuring 3 and 4, we first need to use the Pythagorean theorem and then add that distance to 3 and 4.

By applying the theorem, the square of the hypotenuse equals the sum of the squares of the sides...

d^2=3^2+4^2

d^2=9+16

d^2=25

d=√25

d=5

Thus, the total distance for her run is 5+4+3=12 km

5 0

1 month ago

Read 2 more answers