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polet
9 days ago
7

If line A contains Q(5,1) and is parallel to line MN with M(-2,4) and N(2,1), which ordered pair would be on the perpendicular t

ransversal if its equation is y= 4/3x + 1/3

Mathematics
2 answers:
lawyer [9.2K]9 days ago
6 0
The options you provided are unclear to me, so I will respond in general terms: to determine if a point (ordered pair) lies on a line, you need to substitute the x-value from that pair into the line's equation and check if the resulting y-value matches the y-value of the ordered pair. For example, if your line is y = 4/3x + 1/3, we can check if (0, 0) and (2, 3) fit this line. We find that y = 4/3·0 + 1/3 gives us 1/3, which does not equal 0, indicating (0, 0) is not on the line. For (2, 3), substituting yields y = 4/3·2 + 1/3 = 3, meaning (2, 3) is on the line.
Inessa [8.9K]9 days ago
5 0
The coordinates -1, -1 lie on the line defined by the equation y = 4/3x + 1/3. The following explains the nature of straight-line equations in the Cartesian plane. The general formula is given by y = mx + c, where m represents the slope (gradient) and c is the y-intercept. The gradient (m) can be calculated as Δy / Δx. Important properties of lines include the gradient of a line parallel to the x-axis being 0, while that parallel to the y-axis is undefined. For two parallel lines, their gradients will match, and in the case of two perpendicular lines, the product of their gradients equals -1.
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A students calculation was found to have a 15.6% error, and the actual value was determined to be 25.7 mL. What are the two poss
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The true value is 25.7 ml.
The calculated error is 15.6%.
Thus, the error amount equals 0.156 times 25.7, which calculates to 4.0092 ml.

The percentage error indicates that the student's measurement could either exceed or fall short of the true value by this error amount.

This leads to two potential readings:
one possibility is: 25.7 + 4.0092 = 29.7092 ml
the other possibility is: 25.7 - 4.0092 = 21.6908 ml

8 0
1 month ago
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Both sets of values have an average of 13. Is Set A's standard deviation smaller, larger, or about the same as Set B's? (Note: T
babunello [8412]
Set A's standard deviation exceeds that of Set B. To explain, standard deviation reflects variation within data sets. Generally, a dataset with a narrower range will exhibit a smaller standard deviation. For Set A, the range is 25-1 = 24, while for Set B, it's 18-8 = 10. Given that Set A's range is bigger, we would anticipate its standard deviation to also be larger. Standard deviation is calculated as the square root of the average of the squared deviations from the mean. In Set A, the deviations are ±12, ±11, ±10, whereas Set B's deviations are ±5, ±3, ±1. We can reasonably conclude that the value for Set A will be greater without computing the RMS difference. Thus, Set A's standard deviation is larger compared to Set B.
5 0
2 days ago
What’s the x value of PR=9x-31 and QR=43?
AnnZ [9099]

Reducing

9x + -31 = 43

Rearranging the components:

-31 + 9x = 43

Finding the solution

-31 + 9x = 43

Isolating the variable 'x'.

Shift all terms with x to one side,

Add '31' to both sides of the equation.

0 + 31 + 9x = 43 + 31

Summing up similar items:

-31 + 31 = 0

0 + 9x = 43 + 31

9x = 43 + 31

Summing similar items:

43 + 31 = 74

9x = 74

Split each side by '9'

x = 8.222222222

Simplifying

x = 8.222222222

6 0
1 month ago
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A circle is shown. Secants E G and D G intersect at point G outside of the circle. Secant E G intersects the circle at point F a
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Answer:

Step-by-step breakdown:

The necessary formula for this problem is

6(6+x)=5(5+x+3)

which resolves to

6(6+x)=5(8+x)

leading to

36 + 6x = 40 + 5x, and consequently

x = 4

Thus, DG equals 5 + 4 + 3, resulting in 12

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27 days ago
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westfalls is 7 miles south of edenville and concord is 13 miles west of westfalls. what is the distance from edenville to concor
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Response:

The distance from Endnville to Concord is calculated as 14.8 miles

Step-by-step explanation:

∵ Westfalls is located 7 miles south of Endnville

∵ Concord is situated 13 miles west of Westfalls

∵ South and West are ⊥

∴ The total distance from Endnville to Concord is √(7)² + (13)²

                                                                      = 14.8 miles

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