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Nastasia
2 days ago
12

Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. De

note this by H (the remaining were away games). Of all the games, 25% were wins. Denote this by W (the remaining were losses). Of all the games, 20% were at-home wins. Of the at-home games, we are interested in finding what proportion were wins. Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?A. P(H)B. P(W)C. P(H and W)D. P(H | W)E. P(W | H)
Mathematics
1 answer:
tester [8.8K]2 days ago
6 0

Answer:

E. P(W | H)

Step-by-step explanation:

Meaning of each probability:

P(H): Likelihood of the game occurring at home

P(W): Likelihood of the game resulting in a win.

P(H and W): Likelihood that the game is both at home and a win.

P(H|W): Likelihood of a win occurring when at home.

P(W|H): Likelihood of winning at home games.

Which probabilities are necessary to determine the fraction of home games that were victories?

This is the probability of winning a home game. Hence, the answer is:

E. P(W | H)

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