I thought of number J, and then subtracted half of it from 34.

I’m not really certain, but I think C could be the answer; my apologies if that's inaccurate.

Sample Answer: No, Ingrid's statement is incorrect. In this situation, the starting point is at 170 feet, which denotes the y-intercept. The reduction of 4 feet per year symbolizes the rate of change, or slope. In the slope-intercept equation format, y = mx + b, with 'm' denoting the slope and 'b' signifying the y-intercept, the accurate equation would be y = −4x + 170.

The domain is defined as the complete set of values of variable x for which the function is valid. In this case, the x-axis illustrates time in seconds. Therefore, we must determine all possible time values over which distance can be covered or the function is defined. It’s noted that the sprinter completed the race in 11 seconds, and the start time is 0 seconds. Hence, the value of t ranges from 0 to 11. Therefore, the domain encompasses all real numbers from 0 to 11.

Answer:

The result is 2

Step-by-step explanation:

A segment requires at least 2 points for its construction.

In geometry, a line segment refers to a section of a line defined by two unique endpoints, encompassing all points located along the line segment between these endpoints.

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.