What is the product of (–0.9)(–2.4)?

Answer:

7 years

Step-by-step explanation:

Since a graph isn’t provided, I will indicate how many years are involved, and you should be able to deduce it from this. First, let’s [use a calculator] to find 2% of 250, which equals 5. Adding 5 to the total only slightly impacts 2% of the original amount, changing it by 0.1 or 5/50. We can continue adding 5 until we exceed 282, which occurs after 7 increments, calculated as (285 minus 250) divided by 5. Thus, the answer is indeed 7 years. A quick calculation will confirm this.

Answer:

Option 2  50 ≤ s ≤ 100

Option 5 She can make a deposit of $50

Option 6 She can make a deposit of $75

Detailed explanation:

Let

s represent the amount of money Layla puts into her savings account.

We know that

25% = 25/100 = 0.25

50% = 50/100 = 0.50

Thus

----->

----->

The compound inequality is

Check each case

case 1) 25 ≤ s ≤ 50

This statement is false

Refer to the procedure

case 2) 50 ≤ s ≤ 100

This statement is true

Refer to the procedure

case 3) s ≤ 25 or s ≥ 50

This statement is false

Because s ≤ 100 and s ≥ 50

case 4) s ≤ 50 or s ≥ 100

This statement is false

Because s ≤ 100 and s ≥ 50

case 5) She can make a deposit of $50

This statement is true

As the value of s meets the compound inequality  

case 6) She can make a deposit of $75

This statement is true

As the value of s meets the compound inequality  

Answer:

u(t)  = -(3 + w^2 ) cos t /(1- w^2)cos t + 7 sin t + 8 cos wt /(1- w^2)

Step-by-step explanation:

The characteristic equation is k² + 1 = 0, which leads to k² = -1, resulting in k = ±i.

The roots are k = i or -i.

The general solution takes the form  u(x)=C₁cosx+C₂sinx.

Applying the method of undetermined coefficients, we have

Uc(t) = Pcos wt  + Qsin wt

Calculating the derivatives gives us Uc’(t) = -Pwsin wt  + Qwcos wt

And differentiating again yields Uc’’(t) = -Pw^2cos wt  - Qw^2sin wt

With the equation U’’ + u = 8cos wt, we substitute:

-Pw^2cos wt  - Qw^2sin wt + Pcos wt  + Qsin wt = 8cos wt.

This simplifies to (-Pw^2 + P) cos wt   + (-Qw^2 + Q) sin wt = 8cos wt.

From -Pw^2 + P = 8, we find P= 8  /(1- w^2).

From -Qw^2 + Q = 8, we can conclude Q = 0.

Thus, Uc(t) = Pcos wt  + Qsin wt = 8 cos wt /(1- w^2).

Combining gives us U(t) = uh(t ) + Uc(t)

     = C1cos t + c2 sin t + 8 cos wt /(1- w^2).

Initial conditions yield:

U(0) = C1cos(0) + c2 sin (0) + 8 cos (0) /(1- w^2)

Which leads us to C1 + 8 /(1- w^2) = 5

So C1 = 5 - 8 /(1- w^2) = -(3 + w^2 ) /(1- w^2).

Next, taking the derivative:

U’(t) = -C1 sin t + c2 cos t - 8 w sin wt /(1- w^2).

Evaluating at t = 0 gives us:

U’(0) = -C1 sin (0) + c2 cos (0) - 8 w sin (0) /(1- w^2) = 7.

Thus, c2 = 7.

  u(t)  = -(3 + w^2 ) cos t /(1- w^2)cos t + 7 sin t + 8 cos wt /(1- w^2)

   

Response:

Slope=4

x−intercept=−  

4

16

​  

=−4

b−intercept=  

1

16

​  

=16.0000

Detailed breakdown:

A) The independent variable in this scenario is the quantity of books purchased. C) The overall cost for the year hinges on the number of books obtained. E) The output of this function is the total yearly cost.