What is the domain indicated on the graph for each portion of the piecewise function? f(x) = StartLayout enlarged left-brace 1st

Answer:

mCEA = 90ᴼ, as CEA forms a right angle, and by definition, right angles measure 90ᴼ.

The angle CEF is classified as a straight angle as it combines two right angles (CEA and AEF), equating to 180ᴼ altogether. Straight lines are defined to measure 180ᴼ.

AEF is determined to be a right angle as CEA is already a right angle, and since CEF is a straight line, AEF must also be a right angle.

Answer:

The correct response is: b)

Step-by-step explanation:

a4b=24, where a × 4 × b = 24 implies a × b = 6

The pairs of numbers with a product of 6 include: {1,6} and {2,3}

In base 10, a4b translates to 100a + 40 + b

Calculating gives us:

100×1+40+6=146

100×6+40+1=641

100×2+40+3=243

100×3+40+2=342

Summing these results yields: 146 + 641 + 243 + 342 = 1372

The correct answer is: b)

Answer:

The function decreases across all real numbers x where x < 1.5.

Step-by-step explanation:

We have

This represents an upward-opening vertical parabola

The vertex denotes a minimum point

The vertex is located at (1.5,-6.25)

We know that

The function is decreasing within the interval ----> (-∞, 1.5) x < 1.5

This means----> the function is continuously decreasing for all real x values under 1.5

Conversely, the function is increasing within the interval ----> (1.5, ∞) x> 1.5

Thus, for all real x values greater than 1.5, the function is increasing

Check the attached figure for further clarification

Therefore

The true statement is

The function decreases across all real numbers x where x < 1.5.

Answer:

CrO₃.

Step-by-step explanation:

First, we will find the chromium percentage in the oxide by using the following process:

Oxygen (O) = 48%

Chromium (Cr) =?

The oxide consists solely of chromium and oxygen, and its chromium percentage is calculated as:

Cr = 100 – percentage of oxygen

Cr = 100 – 48

Cr = 52%

Next, we will determine the empirical formula for the oxide:

Chromium (Cr) = 52%

Oxygen (O) = 48%

Now, we divide by their molar mass:

Cr = 52/52 = 1

O = 48/16 = 3

Now, divide by the lowest value:

Cr = 1/1 = 1

O = 3/1 = 3

Thus, the empirical formula for the oxide is CrO₃.