The provided equation is a differential equation that allows for variable separation. You should group similar terms, integrate, use the correct limits, and present V as a function of t. This is achieved in the following manner: dV/dt = -3(V)^1/2, which rearranges to dV/-3V^1/2 = dt. Initially, when V equals 225, after integration, we arrive at -2/3(√V - √225) = t, which can be further detailed as -2/3(√V - 15) = t. This represents the function for V at a specific time t. I trust this information is helpful, have a pleasant day.
5(11 squared + 1) plus 16
5(121 + 1) plus 16
5(122) plus 16
605 plus 16
p(11) equals 626
B. The correct ratio is sen α = BC/b. Step-by-step explanation: Trigonometric identities are utilized for resolving problems involving right angles. In any right-angled triangle, the side opposite to the angle is known as the opposite side, while the adjacent side runs parallel to the angle, ultimately leading to the longest side, called the hypotenuse.
The cubic equation formed is L^3 - 52L +144 = 0. Dimensions: Length = 4 inches, Width = 2 inches, Height = 3 inches. To determine this, let L be the length, W the width, and H the height. The box volume is 24 cubic inches, and its total surface area is 52 sq. inches. Setting W = L/2 leads to Volume = L * W * H, thus substituting W gives us the equation 0.5L^2 * H = 24 resulting in H = 48/L^2. The surface area equation simplifies to (L*W) + (L+H) + (W+H) = 26. Introducing W = 0.5L yields 0.5L^2 + 1.5LH = 26. Substituting H into this gives 0.5L^2 + 72/L = 26. Multiplying throughout by L to eliminate denominators yields 0.5L^3 - 26L + 72 = 0. After multiplying through by 2: L^3 - 52L +144 = 0. Testing L=4 confirms a factor, thus Length (L) = 4 inches, and subsequently, W and H calculate to 2 inches and 3 inches respectively.
