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34kurt
26 days ago
11

Which point lies on the graph of the finite sequence shown?

Mathematics
2 answers:
Leona [12.6K]26 days ago
8 0

Response:

(6,1)

Thank you!:))

Zina [12.3K]26 days ago
4 0
We would need to examine the graph to provide a response, I apologize.
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10 times as many as blank hundreds or 60 hundreds is blank thousands
Svet_ta [12734]

The result of multiplying 10 by 6 hundreds equals 60 hundreds, which can also be expressed as 6 thousands.

Explanation

This can be simplified as follows:

  • 10 times a given quantity of _____ hundreds results in 60 hundreds
  • 60 hundreds convert to _____ thousands

We will divide this into two segments:

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }... Equation-1

\boxed{ \ 60 \times 100) = M \times 1,000 \ }... Equation-2

This straightforward multiplication relates to the place value system. We need to perform calculations to find the values of N and M.

Initially, let's focus on Equation-1.

We will move the variable M to one side of the equation in order to isolate it and solve for its value.

\boxed{ \ 10 \times (N \times 100) = 60 \times 100 \ }

\boxed{ \ 1,000 \times N = 6,000 \ }

Both parts will be divided by 1,000, essentially being multiplied by \frac{1}{1,000}.

\boxed{ \ \frac{1}{1,000} \times 1,000 \times N = \frac{1}{1,000} \times 6,000 \ }

Thus, we conclude with \boxed{\boxed{ \ N = 6 \ }}

Next, we process Equation-2 to derive M's value.

\boxed{ \ 60 \times 100) = M \times 1,000 \ }

\boxed{ \ 6,000 = M \times 1,000 \ }

Rearranging this equation to place M on the left side appears as follows:

\boxed{ \ M \times 1,000 = 6,000 \ }

Again, both sides undergo division by 1,000, which translates to multiplication by \frac{1}{1,000}..

\boxed{ \ \frac{1}{1,000} \times M \times 1,000 = \frac{1}{1,000} \times 6,000 \ }

This results in \boxed{\boxed{ \ M = 6 \ }}

- - - - - - -

Alternative approach for the second step:

60 hundreds equals to __ thousands

\boxed{ \ 6 \times 10 \ hundreds = \ M \ thousands} \ }

\boxed{ \ 6 \times thousands = \ M \ thousands} \ }

\boxed{\boxed{ \ M = 6 \ }}

Additional resources

  1. A more detailed version of this topic
  2. 2 thousands 7 tens divided by 10 equals what?
  3. 100 is equivalent to 1/10 of which number?

Keywords: 10 times as many as, blank, hundreds, 60 hundreds, or, thousands, isolate, operations, multiply, divide, fraction, both sides, equal, the opposite, both sides are multiplied by, divided by, rearrange

4 0
1 month ago
Read 2 more answers
What is the main reason Dylan uses the word uses the word “lonesome” to describe Hattie Carroll’s death?
lawyer [12517]

The correct answer is B. No one stood up for her

The song primarily addresses the racism prevalent in our nation. Dylan highlights that the murderer was not penalized initially; he was released on the night of the homicide due to his wealth, and during the trial, he received only a six-month term instead of a meaningful punishment. Hattie Carroll was largely overlooked in this scenario.

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The First Lady planted rhubarb in the square bed above. Express the perimeter of the rhubarb bed in the terms of x.
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Response:

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Detailed explanation:

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SALES Cars and trucks are the most popular vehicles. Last year, the number of cars sold was 39,000 more than three times the num
PIT_PIT [12445]

Given :

Miki possesses 104 nickels and 88 dimes. She intends to sort her coins into sets where each set has an equal count of both nickels and dimes.

Last year, 216,000 cars were sold.

To Find :

An equation that can identify the number of trucks, t, sold the previous year.

Solution :

Let t represent the quantity of trucks sold and c represent the cars sold.

The statement indicates that the quantity of cars sold exceeded three times the trucks sold by 39,000.

Thus,

c=3t+39000\\\\t=\dfrac{c-39000}{3}

Plugging the value of c = 216000 into the equation above yields :

t=\dfrac{c-39000}{3}\\\\t=\dfrac{216000-39000}{3}\\\\t=59000

This gives us the solution we seek.

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Suppose that you want to mix two coffees in order to obtain 100 pounds of a blend. If x represents the number of pounds of coffe
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Thus, the algebraic expression representing the weight of coffee B is established. Given that x denotes the pounds of coffee A, the total weight for coffee A and coffee B adds up to 100 pounds, leading to an expression for coffee B's quantity.
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