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Art
1 day ago
9

1. Your furniture store sells two types of dining room tables. The first, type A, costs $265 and you make a $25 profit on each o

ne. The second, type B, costs $100 and you make a $13 profit on each one. You can order no more than 40 tables this month, and you need to make at least $760 profit on them. If you must order at least one of each type of table, how many of each type of table should you order if you want to minimize your cost? Possible answers :
20 of type A; 20 of type B
2 of type A; 38 of type B
30 of type A; and 10 of type B
38 of type A; 2 of type B
Mathematics
2 answers:
tester [8.8K]1 day ago
6 0

Response:

1. (5,0)

2. 20 tables of type A; 20 tables of type B

3. no feasible solution

4. -5

5.D

11 -12 7

5 12 -7

6. (-6,8)

All answers are correct, I got you bbs <3

Zina [9.1K]1 day ago
5 0
Let x symbolize the quantity of type A tables and y the number of type B tables.
Minimize: C = 265x + 100y
With constraints: x + y ≤ 40
25x + 13y ≥ 760
x ≥ 1, y ≥ 1

From the graph, the corner points are (20, 20), (39, 1), (30, 1)
Calculating (20, 20): C = 265(20) + 100(20) = $7,300
Calculating (39, 1): C = 265(39) + 100 = $10,435
Calculating (30, 1): C = 265(30) + 100 = $8,050

Hence, to achieve the minimum cost, an order of 20 tables of type A and 20 of type B is advised.
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I have included a screenshot of the entire question along with its accompanying diagram.

Answer:
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Answer:

Attached is the question in consideration.

m\angle CEA =90 \ (deg)

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Step-by-step explanation:

⇒ Given that \ ray\ AE  is ⊥FEC it constitutes a right triangle, leading to m\angle CEA =90\ (deg).

⇒ The measure for \angle BEF =135\ (deg) equals \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB bisects \angle AEC, implying that \angle AEB is half of \angle AEC, thus  \angle AEB = 45\ (deg).

⇒\angle CEF represents a straight line, as the angle measures across it yield 180\ (deg).

⇒ The angle measure for \angle AEF = 90\ (deg) is derived from the linear pair concept.

Since \angle CEA + \angle AEF = 180\ (deg), inserting the values of  m\angle CEA =90\ (deg) leads to \angle AEF = 90\ (deg).

The other two options are incorrect as:

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  • Also, m\angle CEB=2(m\angle CEA) is inaccurate.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

Thus, we have a total 4 valid answers.

The confirmed options are 1,4,5,6.

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