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Effectus
16 days ago
11

A storage pod has a rectangular floor that measures 19 feet by 13 feet and a flat ceiling that is 5 feet above the floor. Find t

he area of the floor and the volume of the pod.
Mathematics
1 answer:
Inessa [8.9K]16 days ago
4 0

Answer:

Area= 247 feet²

Volume= 1235 feet³

Step-by-step explanation:

The storage pod features a rectangular base measuring 19 feet by 13 feet, with a flat ceiling height of 5 feet above.

Calculating the area of the floor yields: length multiplied by width

Length = 19 feet

Width = 13 feet

Area = 19*13

Area = 247 feet²

The volume of the pod can be found by multiplying the area by the height

Height of the pod = 5 feet

Area = 247 feet²

Volume = 247*5

Volume = 1235 feet³

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liquid product with 10% product solids is blended withsugar before being concentrated (removal of water) to obtaina final produc
lawyer [9226]

Answer:

The mass of the water removed is 66.67 kg

Step-by-step explanation:

Given data

The solids blended with sugar make up 10%.

Final product achieved = 15% product.

Final product contains = 15% sugar solids.

The initial product weighs = 200 kg

Solution

Here, we find the needed sugar amount as follows:

The amount of sugar required = 200 × \frac{10}{100}

Thus, the needed sugar = 20 kg

We recognize that total solids = product solids + sugar solids...............1

Also, the initial product equals the final product.

So,

0.20 × 200kg= 0.30 × total mass of the final product

The mass of the final product = 133.33 kg

However,

the final product contains 15% product solids and 15% sugar solids, which means that the amount of product solids equals the sugar solids.

Thus, the mass of water removed = 200 kg - 133.33 kg.

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7 0
1 month ago
An international polling agency estimates that 36 percent of adults from Country X were first married between the ages of 18 and
Leona [9260]

Answer:

(B) 0.2843

Step-by-step explanation:

Let d represent the difference in proportions between Country X and Country Y for adults who first married from ages 18 to 32.

The hypotheses can be stated as

H_{0}: d=0.15

H_{a}: d<0.15

The test statistic can be computed with the formula

z=\frac{p1-p2-0.15}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}} where

  • p1 corresponds to the sample proportion from Country X (0.36)
  • p2 corresponds to the sample proportion from Country Y (0.26)
  • p indicates the pooled proportion of p1 and p2 (\frac{60*0.36+50*0.26}{50+60}=0.31)
  • n1 is the sample size from Country X (60)
  • n2 is the sample size from Country Y (50)

Thus, z=\frac{0.36-0.26-0.15}{\sqrt{{0.31*0.69*(\frac{1}{60} +\frac{1}{50}) }}} is approximately 0.5646

The p-value for this test statistic is approximately 0.2843

The p-value indicates the likelihood that the difference in proportions between a random sample of 60 adults from Country X and a sample of 50 adults from Country Y who were first married at ages 18 to 32 is at least 0.15.

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21 day ago
People at the state fair were surveyed about which type of
Svet_ta [9486]
To respond effectively, one would need a table showing the number of males and females who prefer pink or yellow lemonade at the state fair. Male preferences are captured as Pink Lemonade: 156, Yellow Lemonade: 104, totaling 260. Female preferences recorded as Pink Lemonade: 72, Yellow Lemonade: 48, totaling 120. Overall, totaling: Pink Lemonade: 228, Yellow Lemonade: 152, 380 in sum. P(pink lemonade | female) is computed as 72/(72+48) = 72/120 = 0.6. P(pink lemonade) is calculated as (156+72)/(260+120) = 228/380 = 0.6. Consequently, the events of preferring pink lemonade and being female are independent given P(pink lemonade | female) equals P(pink lemonade) which both equal 0.6.
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3 days ago
In a cash drawer there is $125 in $5 and $10 bills. The number of $10 bills is twice the number of $5 bills. How many of each ty
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Let x denote the count of $5 bills and y signify the count of $10 bills. It can be stated that "the number of $10 bills is twice the number of $5 bills." Thus, y is 2 times x. We can formulate an equation, y = 2x (equation 1). The total value of all bills amounts to $125, allowing us to create another equation: 5*(number of $5 bills) + 10*(number of $10 bills) = 125. That leads to the equation 5(x) + 10(y) = 125 (equation 2). By substituting y = 2x into equation 2, we get 5(x) + 10(2x) = 125. This simplifies to 5x + 20x = 125. Combining like terms yields 25x = 125. Dividing both sides by 25 results in x = 5. By substituting x = 5 in the first equation, we find y = 2(5) = 10. Consequently, there are 5 $5 bills and 10 $10 bills.
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3 days ago
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13 days ago
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