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nikitadnepr
1 month ago
11

What is the value of m in the figure below? If necessary,round your answer to the nearest tenth of a unit

Mathematics
1 answer:
zzz [12.3K]1 month ago
3 0
D. Based on similar triangles, the relationship established is 7/BD = BD / 18, using triangles ABD and BDC. Solving this yields BD^2 = 126. Maintain this format for clarity before applying rounding later. As triangle BDC is a right triangle, we can utilize the Pythagorean Theorem to find m, leading to m^2 = BD^2 + 7^2, which calculates to m^2 = 175—take the square root to find m = 13.22, confirming that the solution is D.
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If t represent the number of tickets purchased for a baseball game, which scenario is modeled by the equation, 32.50t + 5 = 28.7
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Answer: By substituting t with 4, we find that 32.5*4 + 5 yields 135 and 28.75 * 4 + 20 results in the same value of 135, confirming the equation is valid.

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By using 4 as the value for t in the equation, a true statement emerges, indicating that the Burns family will incur a cost of $135 for 4 tickets and parking regardless of whether the choice is lower-level or middle-level seating.

Step-by-step explanation:

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2 months ago
Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy
Leona [12618]

Answer:

Hello! Your question appears to be missing details; here is the complete version

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

Step-by-step explanation:

Ix = 0   Ux = \sqrt{y-9z^2}

Iz = 0   Uz = \frac{\sqrt{y} }{3}

Iy = 5   Uy = 10

This provides a comprehensive solution below

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2 months ago
1. X^4(dy/dx) +x^3y =- sec (xy)<br><br>Integral by separation of variables? <br>​
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Answer:

Step-by-step explanation:

Considering the differential equation x^4(dy/dx) + x^3y = -sec(xy). We will solve it employing the method of separation of variables;

x^{4} \frac{dy}{dx} +x^{3}y = -sec(xy)\\x^{3}(x\frac{dy}{dx} + y) = -sec(xy)\\let \ v=xy\\\frac{dv}{dx} = x\frac{dy}{dx} + y(implicit \ in\ nature)\\

By substituting v and dv/dx into the previous equation, we acquire;

x^{3}\frac{dv}{dx} = -secv

We then separate the variables:

-\frac{dv}{secv} = \frac{dx}{x^{3} }

-cosvdv = x^{-3}dx\\ integrating\ both\ sides\\-\int\limits {cosv} \, dv = \int\limits {x^{-3} } \, dx\\-sinv = \frac{x^{-2} }{-2} + C\\since\ v = xy\\-sinxy = \frac{x^{-2} }{-2} + C\\2sin(xy) = x^{-2} -2C\\2 sin(xy) = \frac{1}{x^{2} } -K (where\ K = 2C)\\

The end expression provides the solution to the differential equation.

8 0
3 months ago
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