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AysviL
9 days ago
8

In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 110.98 g/mol a

nd each beaker must have 250. mL of solution, what mass of CaCl2 would be used? 3.13 g 38.5 g 200 g 617 g
Chemistry
2 answers:
alisha [2.7K]9 days ago
8 0
The result is 200 g. Given that the molar mass of CaCl2 is 110.98 g/mol, this indicates that there are 110.98 g in 1 L of a 1 M solution. Let's calculate the amount of CaCl2 in 0.720 M. Using the proportion 110.98 g: 1 M = x: 0.720 M, we find x to be 79.90 g. Therefore, in 1 L of a 0.720 M solution, there is 79.90 g. Next, we need to create ten beakers with 250 mL each, totaling 10 * 250 mL = 2500 mL or 2.5 L. Then, using the equation 79.90 g: 1 L = x: 2.5 L, we calculate x = 79.90 g * 2.5 L: 1 L, resulting in x = 199.75 g, approximately 200 g.
castortr0y [2.7K]9 days ago
8 0
The answer is C. 200g. Explanation: I just completed the test, and that's the correct answer.
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1 month ago
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A compound composed of only carbon and chlorine is 85.5% chlorine by mass. propose a lewis structure for the lightest of the pos
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The visual representation is displayed in the following image.

For calculations, consider 100 grams of the compound:

ω(Cl) = 85.5% ÷ 100%.

ω(Cl) = 0.855; signifying the mass percentage of chlorine in the compound.

m(Cl) = 0.855 · 100 g.

m(Cl) = 85.5 g; this represents the mass of chlorine.

m(C) = 100 g - 85.5 g.

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n(Cl) = m(Cl) ÷ M(Cl).

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n(C) = 1.21 mol; this is the quantity of carbon.

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The compound in question is identified as dichlorocarbene CCl₂.

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1 month ago
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2) The mass fraction mentioned is superfluous information.

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29 days ago
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