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KatRina
8 days ago
8

On a summer day, you take a road trip through Death Valley, California, in an antique car. You start out at a temperature of 21°

C, but the temperature in Death Valley will reach a peak of 51°C. The tires on your car hold 15.6 L of nitrogen gas at a starting pressure of 249 kPa. The tires will burst when the internal pressure (Pb) reaches 269 kPa. Answer the following questions and show your work.
How many moles of nitrogen gas are in each tire?
• What will the tire pressure be at peak temperature in Death Valley?
• Will the tires burst in Death Valley? Explain.
• If you must let nitrogen gas out of the tire before you go, to what pressure must you reduce the tires before you start your trip? (Assume no significant change in tire volume.)
Chemistry
1 answer:
Anarel [2.7K]8 days ago
4 0
<span>Only one formula should be applied, and we need to consider ideal gas conditions. This formula is: PV=nRT. Manipulate this equation for the subsequent questions to find the solutions.
1. n = PV/RT = (249*1000 Pa)(15.6 L)(1 m^3/1000 L)/(8.314 Pa-m^3/mol-K))(21+273) = 1.59 mol
2. P = nRT/V = (1.59)(8.314)(51+273)/(15.6/1000)(1000) = 274.55 kPa
3. Given that the answer in #2 surpasses 269 kPa, the tires are likely to burst. 4. Lower the pressure significantly below the threshold of 269 kPa.</span>
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Answer: Option (a) is the correct answer.

Explanation:

Under conditions of low pressure and high temperature, gas molecules exhibit negligible attractions or repulsions among themselves. Hence, gases behave ideally in these scenarios.

Conversely, at low temperatures, there is a reduction in the kinetic energy of gas molecules, while high pressure compels the molecules to be closer together.

Thus, attractive forces emerge between molecules in conditions of low temperature and high pressure, causing gases to be termed real gases.

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Suppose a 20.0 g gold bar at 35.0°C absorbs 70.0 calories of heat energy. Given that the specific heat of gold is 0.0310 cal/g °
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The change in temperature can be expressed as:

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By substituting in the known values, we arrive at:

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