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sergeinik
1 month ago
6

To find the distance between (-2,-3) and (4,1), Peggy's teacher drew a diagram and marked blue lines to represent the legs of a

right triangle. Peggy then used 42 and 62 to find the distance represented by the red segment. What distance did she find ?
Mathematics
2 answers:
zzz [12.3K]1 month ago
4 0

Response:

d=2\sqrt{13}\ units

Detailed explanation:

The method to determine the distance between two points is defined as

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

In this case, we have

A(-2,-3)\\B(4,1)  

input the values

d=\sqrt{(1+3)^{2}+(4+2)^{2}}

d=\sqrt{(4)^{2}+(6)^{2}}

d=\sqrt{52}\ units

d=2\sqrt{13}\ units

Inessa [12.5K]1 month ago
3 0
That must be what you are implying.
The distance between the points can be calculated as sqrt(4^2 + 6^2) = sqrt 52  = 2 sqrt13
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Hank and Debra each own two milking cows. One day, they milked their cows and compared the amount of milk the cows produced in t
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Answer:

The result to your inquiry is 2 7/24.

Step-by-step explanation:

Data:

Hank's cows yield = 4 3/4 and 4 1/8

Debra's cows yield = 5 1/2 and 5 2/3

Process:

1.- Convert the mixed numbers into improper fractions:

For Hank: (16 + 3)/4 = 19/4 and (32 + 1)/8 = 33/8.

For Debra: (10 + 1)/2 = 11/2 and (15 + 2)/3 = 17/3.

2.- Add Hank's and Debra's milk quantities:

Hank: 19/4 + 33/8 = 38/8 + 33/8 = 71/8.

Debra: 11/2 + 17/3 = 33/6 + 34/6 = 67/6.

3.- Subtract Hank's total from Debra's total:

67/6 - 71/8 = (268 - 213)/24.

Thus, it simplifies to 55/24.

- Convert back to a mixed number:

2

24 55

7

Where 55/24 equals 2 7/24.

4.- Conclusion:

Debra produced 2 7/24 more milk than Hank.

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Answer:

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

Based on the analysis, the 95% confidence interval is specified as (0.2789;3.055)  

The question regarding the 95% confidence interval's ability to ascertain potential differences in measurements between the two indenters is as follows:

Indeed, the confidence interval does not include the value 0, thus indicating that the Diamond values significantly exceed those of the Steel Ball at a 5% significance level.

Step-by-step explanation:

Here is the dataset in consideration:

specimen    1     2    3     4      5     6     7    8     9

Steel Ball   51   57   61   70   68   54   65  51   53

Diamond   53   55  63   74   69   56   68  51   56

By calculating the differences between diamond and steel ball measurements, we create the dataset:

d: 2, -2, 2, 4, 1, 2, 3, 0, 3

In the next step, we compute the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.667

Following that, we determine the standard deviation of the differences, arriving at:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =1.803

A confidence interval refers to "a range of values that’s likely to encompass a population value with a certain level of confidence. It is typically expressed as a percentage indicating where a population mean falls within an upper and lower limit."  

The margin of error represents the extent to which values diverge above and below the sample statistic in a confidence interval.  

Normal distribution, is described as a "probability distribution that is symmetric about the mean, illustrating that data points close to the mean occur more frequently than those further away."  

The confidence interval for the mean is derived using the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

To calculate the critical value t_{\alpha/2}, we first determine the degrees of freedom using:  

df=n-1=9-1=8  

Given a confidence level of 0.95 or 95%, the appropriate critical value can be found using Excel, a calculator, or a table. The Excel command would be: "=-T.INV(0.025,9)". Therefore, we observe that t_{\alpha/2}=2.31.

Finally, we can substitute all our findings into formula (1):  

1.667-2.31\frac{1.803}{\sqrt{9}}=0.2789  

1.667+2.31\frac{1.803}{\sqrt{9}}=3.055  

In this case, the 95% confidence interval is calculated as (0.2789;3.055)  

In determining if the two indenters yield distinct measurements, we find that the confidence interval does not enclose zero, allowing us to conclude that Diamond readings greatly surpass Steel Ball readings at the 5% significance level.

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1 month ago
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