Player V and Player M have competed against each other many times. Historical data show that each player is equally likely to wi

The correct response is D; we can treat the survey as one involving a single variable, responding with either "yes, I attended more than 4 games" or "no." Given the random survey of 10 students meets the randomization criterion and that their responses are independent, options B and C can be dismissed. However, since only 10 students were surveyed, the confidence interval will not be narrow. As per Statistical Solutions, a minimum of 10 subjects per variable is essential for regression analysis. If the query concerns the number of games each student attended, the potential variables increase; conversely, if it solely asks, “Did you attend more than 4 games?”, then we only consider a single variable, making 10 students sufficient.

Answer:

Therefore, the data is best represented by:

Step-by-step explanation:

We have a table indicating the estimated lines of code produced by computer programmers per hour when x individuals are engaged.

The question asks which model accurately reflects this data.

To determine this, we will substitute the values of x into each function to see which one accurately produces the corresponding y (f(x)) values provided in the table:

We are presented with four functions, which are:

A)

B)

C)

D)

We'll create a table displaying these values at various x levels.

x                  A                 B                C               D

2              66.66          49.3            52.5           50

4             94.57            71.44           106.3         104  

6             134.14           103.57         160.1          158

8             190.27          150.14          213.9         212

10           269.91           217.64         267.7         266

12           382.85          315.5           321.5          320.

Thus, the function that suitably represents the data is:

Option C.

y=26.9x-1.3

P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'

The likelihood of answering each question correctly stands at 1/4, given that there is 1 correct answer out of 4 choices. Therefore, the probability of answering 15 questions correctly is computed as (1/4)^15 = 1/1073741824.