Name three common measurements that are expressed as a ratio of two units.

F(x) = 1,000. 70n - 400 = 1,000. 70n = 1,000 + 400. 70n = 1,400. n = 1,400/70. n = 20. The instructor requires 20 students.

Let x represent the number of caps

cost per cap = $6

cost for x caps = 6x

shipping charge = $25

overall budget = $1000

We can set up the following inequality:

Because the total amount cannot exceed 1000, we have

25 + 6x ≤ 1000

6x ≤ 975

x ≤ 162.5

rounding,

x ≤ 163

This means she can purchase a maximum of 163 caps.

A) The cost to send a package that weighs 3.2 pounds is $4.13. Since this weight exceeds 3 pounds but remains below 4 pounds, we have to refer to the pricing that applies to 4-pound packages (see the attached document for pricing details).

b) To illustrate the Media Mail shipping costs based on the weight of the books, a line graph is appropriate. In this graph, the weight in pounds is represented on the x-axis and the shipping costs on the y-axis.

c) The graph depicting the Media Mail shipping costs as a function of book weight will be represented by the equation: f(x) = 2.69 + 0.48(x-1)

The provided values are

$85 $240 $120 $60 $315 $190 $145 $105 $285 $260 $95 $215 $235 $175 $155

To start, we will arrange these in ascending order

resulting in

$60 $85 $95  $105  $120  $145 $155 $175 $190 $215 $235 $240 $260 $285 $315

The total count is 15

the position of 105 is 4

Now, we can calculate the percentile

Thus, the percentile for the bid of $105 is 26.667%...........Response

Answer: The mean and variance of Y are $0.25 and $6.19 respectively.

Step-by-step explanation:

The scenario is as follows: You and a friend participate in a game involving tossing a fair coin.

The sample space for tossing two coins is {TT, HT, TH, HH}

Let Y represent the earnings from one round of the game.

If both faces are heads, you win $1; therefore, P(Y=1)=P(TT)=

You win $6 if both faces are heads, so P(Y=6)=P(HH)=

If the faces do not match, you lose $3 which means P(Y=1)=P(TH, HT)=

To find the expected value to win: E(Y)=

Thus, the mean of Y: E(Y)= $0.25

Variance =

Therefore, variance of Y = $ 6.19