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Vsevolod
1 month ago
13

Suppose an ant is sitting on the perimeter of the unit circle at the point (1,0). if the ant travels a distance of 2π3 in the co

unter-clockwise direction, then the coordinates of the point where the ant stops will be

Mathematics
2 answers:
AnnZ [12.3K]1 month ago
6 0
I may be mistaken, but I believe it's (1,2Π3-1)
Svet_ta [12.7K]1 month ago
5 0

Conclusion:

The coordinates where the ant comes to a stop are (0,1)

Detailed explanation:

We start with the ant positioned on the perimeter of the unit circle at (1,0). If it moves a distance of 2\pi^3 counterclockwise, we must determine the coordinates of where the ant halts.

The ant begins at point A.

The circumference of the unit circle is=2πr=2π(1)=2π units

The ant travels a distance of 2\pi^3.

To find the number of complete circles made, we can divide by 2π

(This corresponds to the first circle)

\frac{2\pi^3}{2\pi}=\pi^2       (This pertains to the second circle)

\frac{\pi^2}{2\pi}=\frac{\pi}{2}After fully completing the first circle, only the first quadrant of the second circle remains.

As a result, the coordinates of the stopping point for the ant will be (0,1)

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1)

The score and corresponding probabilities are shown in the following table:

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X = Miguel's score on the Water Hole

The expected value of the variable X can be represented as:

E(X)=\sum x_i p_i

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x_i represents the different possible outcomes of X

p_i denotes the associated probabilities

Accordingly, the expected value of Miguel's score is calculated as follows:

E(X)=3\cdot 0.15 + 4\cdot 0.40 + 5\cdot 0.25 + 6\cdot 0.15 + 7\cdot 0.05=4.55

2)

Here, we will again consider:

X = Miguel's score on the Water Hole

In this case:

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E(X)=4.2

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p(L)=0.4

Consequently, the chance of failure in a long hit is

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Thus, the expected value of X when opting for the long hit strategy is:

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E(X)=4.55

Given that the expected value for X is smaller (which is better) when utilizing the short hit option, we can conclude that this approach is superior.

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