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lilavasa
26 days ago
5

A uniform bar of length l and weight w is attached to a wall with a hinge that exerts a horizontal force hx and a vertical force

hy on the bar. the bar (which makes an angle θ with respect to wall) is held by a cord that makes a 90◦ angle with respect to bar. what is the magnitude of the tension t in the cord?
Mathematics
1 answer:
babunello [11.8K]26 days ago
4 0
The formula is Hx = ½ Wsin θ cos θ
The rationale behind this is:
By examining the torques on the bar, considering the hinge at the rotation axis, the equation constructed would be: ∑T = LT – (L/2 sin θ) W = 0
Thus, T = 1/2 W sin θ. For the forces acting on the bar, we have: ∑fx = Hx – T cos θ = 0. Inserting the value of T into the equation, the result is:∑T = LT – (L/2 sin θ) W = 0
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