The balanced chemical equation for the neutralization of HCl with 
is:
Given weight of = 5g
Moles of = 
Volume of HCl solution = 
Assuming the density of the solution is 1.0 g/mL
Mass of HCl solution = 50 g
Overall mass of the solution = 50 g + 5 g = 55 g
To find the heat of neutralization, we calculate:
Q = m C ΔT
where m equals the mass of the solution = 55 g
C represents the specific heat capacity of the solution = 4.184
ΔT signifies the temperature change = 6.8 K = (6.8 - 273) C = -266.2
The enthalpy of neutralization per mole of
= 
Noble gas notation serves as a condensed form of indicating electron configurations. This notation employs the symbol for the preceding noble gas in the electron configuration of an element. For antimony, the noble gas prior is Kr, which means Xe is not used in its electron configuration. Similarly, for radium, the prior noble gas is Rn, whereas, for uranium, it is also Rn. However, for cesium, the preceding noble gas is Xe, thus it is utilized in the noble gas notation for Sb, specifically written as: Cs: [Xe] 6s.
Answer: cesium
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Response:
9.9 ml of 0.200M NH₄OH(aq)
Reasoning:
3NH₄OH(Iaq) + FeCl₃(aq) => NH₄Cl(aq) + Fe(OH)₃(s)
What volume in ml of 0.200M NH₄OH(aq) will fully react with 12ml of 0.550M FeCl₃(aq)?
1 x Molarity of NH₄OH x Volume of NH₄OH Solution(L) = 2 x Molarity of FeCl₃ x Volume of FeCl₃ Solution
1(0.200M)(Volume of NH₄OH Soln) = 3(0.550M)(0.012L)
=> Volume of NH₄OH Soln = 3(0.550M)(0.012L)/1(0.200M) = 0.0099 Liters = 9.9 milliliters
Option d is the correct choice, as both belong to the alkali metals category (group one).
