One of the conditions is Cancer.
Details:
The equation to calculate work done is defined as follows.
W = 
where, k = proportionality constant = 
d = separation distance = 0.45 nm = 
Now we will insert the given values into the formula above to compute the work done as follows.
W =
= ![\frac{-[8.99 \times 10^{9} Jm/C^{2} \times 3.2 \times 10^{-19} C \times -3.2 \times 10^{-19} C]}{0.25 \times 10^{-9} m}](https://tex.z-dn.net/?f=%5Cfrac%7B-%5B8.99%20%5Ctimes%2010%5E%7B9%7D%20Jm%2FC%5E%7B2%7D%20%5Ctimes%203.2%20%5Ctimes%2010%5E%7B-19%7D%20C%20%5Ctimes%20-3.2%20%5Ctimes%2010%5E%7B-19%7D%20C%5D%7D%7B0.25%20%5Ctimes%2010%5E%7B-9%7D%20m%7D)
= 
Thus, we can conclude that the work needed to increase the distance between the two ions to infinity is 
.
Answer:
B
Explanation:
Flammable substances contain chemicals that react with flames, thus making it their chemical property, particularly when they encounter other materials that cause a reaction.
Hi,
Due to calcium hydroxide being a strong base, its full dissociation will yield both calcium and hydroxyl ions:
Thus, the concentration of hydroxyl ions mirrors that of the calcium hydroxide, allowing for the calculation of pOH as demonstrated below:
Now, pH relates to pOH as:
Consequently, the final pH is achieved.
Best regards.
Fe 3+ + SCN- --> FeSCN 2+
<span>.......Fe 3+.......SCN-.........FeSCN 2+ </span>
<span>I.......0.04..........0.001.............. </span>
<span>C........-x...............-x............. </span>
<span>E.....0.04-x.....0.001-x...........x </span>
<span>Keq = 203.4 = x / (0.04-x)(0.001-x) </span>
<span>203.4 = x / (x^2 - 0.041x + 4x10^-5) </span>
<span>203.4x^2 - 8.34x + 0.00094 = x </span>
<span>203.4x^2 - 9.34x + 0.00094 = 0 </span>
<span>x = -0.0001M or 0.0458M </span>
<span>therefore, according to the calculated Keq, all of the SCN- and Fe 3+ would be fully converted into FeSCN 2+</span>
