A sample of water with a mass of 587.00 kg is heated with 87 kJ of energy to a temperature of 518.4 K. The specific heat of wate r is 1 J-1 kg K-1. What is the initial temperature of the water?
2 answers:
Answer:
370.2 K
Explanation:
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The specific heat capacity of water is known to be 4.187 kJ/(kg.K)
Using the formula q = mCΔT
we can find ΔT = q/mC = 87 kJ/[587.00 kg x 4.187 kJ/(kg.K)] = 87 kJ/(2547.8 kJ/K)
= 0.035 K
To find the initial temperature, Ti = Tf - ΔT = 518.4 K - 0.0354 K = 518.365 K
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