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Brut
3 months ago
5

Assuming that only the listed gases are present, what would be the mole fraction of oxygen gas be for each of the following situ

ations?
A gas sample of 2.31 atm of oxygen gas and 3.75 atm of hydrogen gas that react to form water vapor. Assume the volume of the container and the temperature inside the container does not change.​
Chemistry
1 answer:
eduard [2.7K]3 months ago
6 0

Mole fraction of oxygen gas: 0.381

Additional clarification

Given:

2.31 atm Oxygen

3.75 atm Hydrogen

Required:

Mole fraction of Oxygen

Calculation:

According to Dalton’s Law of partial pressures

P tot = P₁ + P₂ +.. + Pₙ

Substituting values:

P tot = P O₂ + P H₂

P tot = 2.31 atm + 3.75 atm

P tot = 6.06 atm

Mole fraction of O₂ (X O₂):

P O₂ = X O₂ x P tot

X O₂ = P O₂ / P tot

X O₂ = 2.31 / 6.06

X O₂ = 0.381

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