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MakcuM
22 hours ago
9

On Monday, Amie rides her bike from home to school. After school, she bikes to work. After work, she bikes home. Based on the in

formation in the diagram below, about how many miles does Amie bike on Monday?
Mathematics
2 answers:
zzz [9K]22 hours ago
4 0
To obtain a complete response, the diagram would be essential. However, to approximate the solution, I'd calculate the distances from her home to her school and combine that with the stretch from school to work, and finally, from work back home. If there’s no information regarding the distance from work to home, I’d simply double the traveled distance already accounted for.
Zina [9.1K]22 hours ago
3 0

The answer is D: 13.1 miles

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The value of x is 12. This can be found using the Pythagorean theorem with c equal to 13 and b equal to 5, where a equals x.
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10 days ago
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If m∠7 = 55°, which of the following statements are true? Select all that apply. There are two horizontal parallel lines are cut
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Answer:

The accurate assertions include:

A. m∠6 = 55°

C. m∠1 + m∠4 = 250°

D. m∠1 + m∠6 = m∠7 + m∠4

Step-by-step clarification:

The provided information is as follows:

m∠7 = 55°

The angles formed by the transversal and the upper horizontal parallel line are (starting from the top left and moving in clockwise direction) 1, 2, 4, 3

Likewise, the angles from the transversal and the lower horizontal parallel line are (starting from the top left and going clockwise) 5, 6, 8, 7

Consequently, we have;

m∠7 ≅ m∠6 (Vertically opposite angles are equal)

Thus, m∠6 = m∠7 = 55°

m∠6 = 55°, which aligns with option A.

m∠5 + m∠6 = 180° (The sum of angles on a straight line)

So, m∠5 = 180° - m∠6 = 180° - 55° = 125°

m∠5 = 125°

m∠1 ≅ m∠5 (Corresponding angles)

Thus, m∠1 = m∠5 = 125°

m∠1 ≅ m∠4 (Vertically opposite angles)

Therefore, m∠1 = m∠4 = 125°

Thus, m∠1 + m∠4 = 125° + 125° = 250°

m∠1 + m∠4 = 250°, which corresponds to option C.

m∠1 ≅ m∠4 (Vertically opposite angles)

m∠6 ≅ m∠7 (Vertically opposite angles)

Thus, m∠1 + m∠6 = m∠7 + m∠4 (Transitive property), which matches option D.

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11 days ago
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Lines EA and FG could be perpendicular to RS.
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The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th
AnnZ [9099]

Respuesta:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Explicación paso a paso:

La probabilidad (P) de encontrar la partícula está dada por:

P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx  

P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx     (1)

La solución de la integral de la ecuación (1) es:

P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}  

(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}    

(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}  

(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}    

(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5

(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:

P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}

Espero que te ayude.

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3 days ago
Naomi and Hudson work at a dry cleaners ironing shirts. Naomi can iron 35 shirts per hour, and Hudson can iron 20 shirts per hou
Inessa [9000]
To formulate a system of equations for Naomi and Hudson, who work at a dry cleaners where Naomi can iron 35 shirts per hour and Hudson can manage 20 shirts per hour, we know that together they worked 13 hours and completed a total of 395 shirts. Naomi, during her 13 hours, could potentially iron 455 shirts (13 x 35), meaning each hour Hudson worked lessens that number by 15 shirts. The difference of 60 shirts (455 - 395) indicates that Hudson worked for 3 hours and Naomi, therefore, for 10 hours. The resulting equation reflects this relationship: 35Y + 20X = 395.
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