answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ede4ka
1 month ago
13

In a GP if T3 = 18 and T6 = 486 Find:- T10

Mathematics
2 answers:
lawyer [12.5K]1 month ago
8 0

Answer:

The 10th term in the geometric progression is 29.

Step-by-step explanation:

Given: In a geometric series, [T3 = 18] and [T6 = 486].

To find: The term [T10]?

Solution:

A geometric sequence takes the form [a, ar, ar^2,...]

Where, a represents the first term, and r denotes the common ratio.

The nth term is expressed as [Tn = a * r^(n-1)]

From the information provided: [T3 = a * r^2 = 18]

And [T6 = a * r^5 = 486]

By dividing the second equation by the first:

[(a * r^5) / (a * r^2)] = 486 / 18

[r^3 = 27]

Taking the cube root provides: r = 3.

Inserting r into one of the equations allows us to solve for a.

Substituting r gives: [T3 = a * r^2 = 18]

Thus, the first term is a = 2, and the common ratio is r = 3.

The 10th term in the geometric progression is computed as:

[T10 = a * r^(10-1)]

[Thus, T10 = 29.]

Zina [12.3K]1 month ago
5 0

Answer:

T10 = 39366

Step-by-step explanation:

In this geometric sequence, the third term equals 18, and the sixth term is 486.

We seek to determine the 10th term.

In a geometric progression, the nth term can be represented as:

[Tn = T1 * r^(n-1)]

where r signifies the common ratio, and T1 symbolizes the first term.

Given values: T3 = 18 and T6 = 486.

By solving these relationships:

Dividing the sixth term by the third term yields:

[T6 / T3 = r^3 = 486 / 18]

This results in: r = 3.

After establishing the ratio, we can input it into either term's formula:

To find T1, rearange: [T3 = T1 * r^2 = 18]

Thus dividing yields: T1 = 2.

Consequently, T10 = 39366.

You might be interested in
Bridgette opened a store credit card to purchase a business suit for $463. She put the entire purchase on the credit card. Her A
Inessa [12570]
Begin by determining the monthly interest rate as follows:
\frac{14.99}{12}=1.25
<span>Each month, we deduct the monthly rate and the 5% payment from $463, leading to the following formula:</span>
463(1-(0.05+0.0125))^3=463\times0,9375^3\\=381.5
<span>
Therefore, after three months, Bridgette will have a remaining balance of $381.5 in her account.</span>
5 0
1 month ago
Tamara and Amir shared a candy bar. Tamara ate two fifths. Amir ate two fifths. How much is left?
zzz [12365]

Answer:

1/5

Step-by-step explanation:

Amir and Tamara each consumed 2/5 of the candy bar.

The total consumed is 2/5 + 2/5 = 4/5.

Since 4/5 of the candy bar has been eaten, 1/5 remains.

This is because 5/5 minus 4/5 equals 1/5.

(Note that 5/5 represents a whole candy bar).

7 0
2 months ago
Two functions are shown in the table below. Function 1 2 3 4 5 6 f(x) = −x2 + 4x + 12 g(x) = −x + 6 Complete the table on your o
Svet_ta [12734]

For \fbox{\begin \\\math{x}=6\\\end{minispace}} the function f(x)=-x^{2} +4x+12 and g(x)=-x+6 both yield the same result.

Detailed breakdown:  

The functions involved are

f(x)=-x^{2}+4x+12

g(x)=-x+6

Step 1:  

Insert x=1 in f(x)=-x^{2} +4x+12 to find the value of f(1).

f(1)=-1^{2} +4(1)+12\\f(1)=-1+4+12\\f(1)=15

Insert x=1 in g(x)=-x+6 to find the value of g(1).

g(1)=-1+6\\g(1)=5

Step 2:

Insert x=2 in f(x)=-x^{2} +4x+12 to obtain the value of f(2).

f(2)=-2^{2} +4(2)+12\\f(2)=-4+8+12\\f(2)=16

Substitute x=2 into g(x)=-x+6 to find the value of g(2).

g(2)=-2+6\\g(2)=4

Step 3:

Replace x=3 in f(x)=-x^{2} +4x+12 to find the value of f(3).

f(3)=-3^{2} +4(3)+12\\f(3)=-9+12+12\\f(3)=15

Also, replace x=3 in g(x)=-x+6 to find the value of g(3).

g(3)=-3+6\\g(3)=3

Step 4:

Insert x=4 in f(x)=-x^{2} +4x+12 to find the value of f(4).

f(4)=-4^{2} +4(4)+12\\f(4)=-16+16+12\\f(4)=12

Also, replace x=4 in g(x)=-x+6 to obtain the value of g(4).

g(4)=-4+6\\g(4)=2

Step 5:

Insert x=5 in f(x)=-x^{2} +4x+12 to obtain the value of f(5).

f(5)=-5^{2} +4(5)+12\\f(5)=-25+20+12\\f(5)=7

Replace x=5 in g(x)=-x+6 to find the value of g(5).

g(5)=-5+6\\g(5)=1

Step 6:

Insert x=6 into f(x)=-x^{2} +4x+12 to find the value of f(6).

f(6)=-6^{2} +4(6)+12\\f(6)=-36+24+12\\f(6)=0

Also, substitute x=6 in g(x)=-x+6 to obtain the value of g(6).

g(6)=-6+6\\g(6)=0

Step 7:

According to the provided condition f(x)=g(x).

(a). Insert f(x)=-x^{2} +4x+12 and g(x)=-x+6 into the previously mentioned equation.

-x^{2} +4x+12=-x+6

(b). Multiply through by -1 on both sides.

x^{2} -4x-12=x-6

(c). Move the term x-6 to the left side of the equation.

x^{2} -4x-12-x+6=0\\x^{2} -5x-6=0

(d). Divide the middle term so that its sum equals 5 and the product equals 6.

x^{2} -(6-1)x-6=0\\x^{2} -6x+x-6=0\\x(x-6)+1(x-6)=0\\(x+1)(x-6)=0\\x=-1,6

From the analysis above, it is noted that for x=6 both functions f(x) and g(x) yield the same outcome.

Using a direct approach:

f(x)=g(x)\\\Leftrightarrow-x^{2} +4x+12=-x+6\\\Leftrightarrow-x^{2} +4x+12+x-6=0\\\Leftrightarrow-x^{2} +5x+6=0\\\Leftrightarrow-x^{2} +6x-x+6=0\\\Leftrightarrow x^{2} -6x+x-6=0\\\Leftrightarrow x(x-6)+1(x-6)=0\\\Leftrightarrow(x+1)(x-6)=0\\\Leftrightarrow x=6,-1

The table representing function f(x)=-x^{2} +4x+12 and g(x)=-x+6 is included below.

For more information:

1. What is the y-intercept of the quadratic function f(x) = (x – 6)(x – 2)? (0,–6) (0,12) (–8,0) (2,0)

2. Which is the graph of f(x) = (x – 1)(x + 4)?

6 0
22 days ago
Find the point on the circle x^2+y^2 = 16900 which is closest to the interior point (30,40)
Leona [12618]

Response-

(78,104) represents the point closest to the interior.

Explanation-

The equation defining the circle,

\Rightarrow x^2+y^2 = 16900

\Rightarrow y^2 = 16900-x^2

\Rightarrow y = \sqrt{16900-x^2}

Since the point lies on the circle, its coordinates must be,

(x,\sqrt{16900-x^2})

The distance "d" from the point to (30,40) can be calculated as,

=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

=\sqrt{(x-30)^2+(\sqrt{16900-x^2}-40)^2}

=\sqrt{x^2+900-60x+16900-x^2+1600-80\sqrt{16900-x^2}}

=\sqrt{9400-60x-80\sqrt{16900-x^2}}

Next, we need to determine the value of x for which d is minimized. The minimum distance occurs when 9400-60x-80\sqrt{16900-x^2} is at its lowest value.

Let’s set up the equation,

\Rightarrow f(x)=9400-60x-80\sqrt{16900-x^2}

\Rightarrow f'(x)=-60+80\dfrac{x}{\sqrt{16900-x^2}}

\Rightarrow f''(x)=\dfrac{1352000}{\left(16900-x^2\right)\sqrt{16900-x^2}}

We find the critical points,

\Rightarrow f'(x)=0

\Rightarrow-60+80\dfrac{x}{\sqrt{16900-x^2}}=0

\Rightarrow 80\dfrac{x}{\sqrt{16900-x^2}}=60

\Rightarrow 80x=60\sqrt{16900-x^2}

\Rightarrow 80^2x^2=60^2(16900-x^2)

\Rightarrow 6400x^2=3600(16900-x^2)

\Rightarrow \dfrac{16}{9}x^2=16900-x^2

\Rightarrow \dfrac{25}{9}x^2=16900

\Rightarrow x=\sqrt{\dfrac{16900\times 9}{25}}=78

\Rightarrow x=78

Then,

\Rightarrow f''(78)=\dfrac{1352000}{\left(16900-78^2\right)\sqrt{16900-78^2}}=\dfrac{125}{104}=1.2

Since f''(x) is positive, the function f(x) achieves its minimum at x=78

When x is set to 78, the corresponding y value will be

\Rightarrow y = \sqrt{16900-x^2}=\sqrt{16900-78^2}=104

This leads us to conclude that the closest point is (78,104)

5 0
1 month ago
Maggie is considering two investments. Investment A Investment B Principal $10,000 $8,000 Interest rate 3% 2.8% Time in years 5
Zina [12379]
To determine this, we will apply the simple interest formula: A=P(a+rt)
where
A signifies the total amount.
P indicates the principal amount.
r represents the interest rate in decimal.
t denotes the time period in years.

Investment A. The initial investment amount is $10,000, so P=10000. The investment period is 5 years, meaning t=5. To express the interest rate in decimal, divide it by 100%
r= \frac{3}{100} =0.03
Now, we can substitute these values into our formula to find A:
A=P(a+rt)
A=10000(1+0.03*5)
A=11500

Investment B. P=8000, t=15, and r= \frac{2.8}{100} =0.028.
A=P(a+rt)
A=8000(1+0.028*15)
A=11360

In conclusion, investment A will yield a greater value than investment B at the investment period's conclusion.
3 0
1 month ago
Read 2 more answers
Other questions:
  • I do not understand how to do this at all. Will someone please help me???
    11·1 answer
  • HELP ASAP!!! (25 points and I’ll mark brainliest!!!!)
    5·1 answer
  • By visual inspection, determine the best-fitting regression model for the data plot below
    5·2 answers
  • Kevin cycles 18 miles every morning as part of his exercise. The time it takes him to complete the distance varies inversely as
    12·2 answers
  • students in art class make square tiles that are 5 inches long. they plan to make a row of tiles that is 4 feet 2 inches long.ho
    10·2 answers
  • TIMED HURRY PLEASE!!!!!!!! the first three steps in writing f(x) = 40x + 5x2 in vertex form are shown. Write the function in sta
    5·2 answers
  • A survey of 132 students is selected randomly on a large university campus. They are asked if they use a laptop in class to take
    12·1 answer
  • A bag of garden soil weighs 38 pounds and holds 4 cubic feet. Find the weight of 15 bags in kilograms and the volume of 15 bags
    5·1 answer
  • In triangle ABC, AB = 90 in., BC = 80 in., and angle B measures 50°. What is the approximate perimeter of the triangle?
    11·2 answers
  • Two parallel lines are intersected by a third line so that angles 1 and 5 are congruent. 2 parallel horizontal lines are interse
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!