All categories

21 day ago

PLEASE HELP!

Mathematics

2 answers:

PIT_PIT [9K]21 day ago

8 0

To replicate the BAC angle, the next action is to extend the DE ray away from the BAC angle

Further explanation

Angles are formed by two rays that originate from the same point

Common terminology includes vertex, corner, and angle measure

Typically, angles are expressed in degrees

Angles can be identified using a single letter related to the vertex or through three letters, with the vertex placed between two others

Steps to duplicate the BAC angle:

1. Construct the DE line

2. With a compass, draw a circle centered at A. This circle will intersect lines BA and BC at points F and G

3. Utilize the segment tool to form a segment from the drawn circle's radius
4. Use the Compass to select the AG radius segment
5. Create a circle centered at D with the same radius as AG

6. Label where this circle intersects with the DE as H

7. Construct the FG segment, using the compass tool on this segment

8. Draw a circle centered at H, intersecting the previous circle centered at D at point I

9. Draw the DI line

Thus, BAC is congruent to HDI

Learn more

circumference of the circle

chord, diameter

steps for angle duplication

Keywords: circle, angle duplication, segment tool, compass tool, radius

PIT_PIT [9K]21 day ago

8 0

Answer: Identify the intersection point of circle D and line DE

Step-by-step explanation:

You might be interested in

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

Svet_ta [9481]

Answer:

Here’s the response provided

Step-by-step explanation:

Referring to the flask diagram, the diameter of the cylinder measures 1 inch and its height (h) is 3 inches. Thus, the radius of the cylinder (r) = diameter / 2 = 1/2 = 0.5 inch

The volume of the cylinder can be calculated as πr²h = π(0.5)² × 3 = 2.36 in³

As for the sphere, its diameter is 4.5 in. Hence, the radius of the sphere R = diameter / 2 = 4.5/2 = 2.25 in

The volume of the sphere is calculated as 4/3 (πR³) = 4/3 × π × 2.25³ = 47.71 in³

The total volume of the flask = Volume of the cylinder + Volume of the sphere = 2.36 + 47.71 = 50.07 in³

<pWhen the cylinder and the sphere are expanded by a scale factor of 2, the height (h') of the cylinder becomes 3/2 = 1.5 inches and the radius (r') becomes 0.5/2 = 0.025 inches.

The new volume for the cylinder = πr'²h' = π(0.25)² × 1.5 = 0.29 in³

For the sphere, the new radius is R' = 2.25 / 2 = 1.125 in.

The new volume of the sphere = 4/3 (πR'³) = 4/3 × π × 1.125³ = 5.96 in³

Thus, the new volume of the flask = The new volume of the cylinder + The new volume of the sphere = 0.29 + 5.96 = 6.25 in³

<pThe ratio of the new volume to the original volume = New Volume of the flask / Volume of the flask = 6.25 / 50.07 = 1/8 = 0.125<pThe resulting volume will thus be 0.125 times the original volume

6 0

27 days ago

Talia wants to write the equation of the graphed line in point-slope form. These are the steps she plans to use:

Zina [9154]

Examining Talia's steps to derive the line equation, we identify the erroneous step as detailed below:
Step 1:
Select a point on the line, such as (2,5)
Step 2:
Select another point on the line, such as (1, 3)
Step 3:
Measure units to find the slope. The line moves 1 unit to the right and 2 units upward, resulting in a slope of
(5-3)/(2-1) = 2/1 = 2
Step 4:
Apply these values in the point-slope form
y - y1 = m(x - x1)
y - 3 = 2(x - 1)
y = 2x + 1
Hence, the conclusion is:
Step 4 is erroneous due to incorrect application of (1, 3) in the point-slope format.

4 0

1 month ago

Read 2 more answers

A nationwide survey of 100 boys and 50 girls in the first grade found that the daily average number of boys who are absent from

Leona [9260]

The formula to calculate the difference between two standard deviations of populations n1 and n2 is:
sigma (difference)=√(sigma1/n1 + sigma2/n2). For this scenario:

sigma(d)= √(49/100 + 36/50)

Thus, the calculated standard deviation of the difference equals 1.1.

6 0

17 days ago

Read 2 more answers

Evaluate ∫SF⃗ ⋅dA⃗ , where F⃗ =(bx/a)i⃗ +(ay/b)j⃗ and S is the elliptic cylinder oriented away from the z-axis, and given by x2/

Inessa [8979]

Respuesta:

Por lo tanto, la integral de superficie es $\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c$ .

Explicación paso a paso:

La función dada es,

$\vec{F}=\frac{bx}{a}\uvec{i}+\frac{ay}{b}\uvec{j}$

Para encontrar,

$\int\int_{S}\vec{F}dS$

donde S=A=superficie del cilindro elíptico debemos aplicar el teorema de divergencia, así que,

$\int\int_{S}\vec{F}dS$

$=\int\int\int_V\nabla.\vec{F}dV$

$=\int\int\int_V(\frac{b}{a}+\frac{a}{b})dV$

$=\frac{a^2+b^2}{ab}\int\int\int_VdV$

$=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}$

$=\frac{a^2+b^2}{ab}\times \pi ab\times 2c=\pi (a^2+b^2)c$

Si el vector unitario $\cap{n}$ está dirigido en dirección positiva (hacia afuera), entonces z=c y,

$\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1}. dA$

$=\int\int_{S_1}.dA=0$

Si el vector unitario $\cap{n}$ está dirigido en dirección negativa (hacia adentro), entonces z=-c y,

$\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA$

$=\int\int_{S_2}. -dA=0$

Por lo tanto, la integral de superficie sin el vector unitario de la superficie es,

$\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c$

5 0

1 month ago

On a coordinate plane, 3 triangles are shown. Triangle B C D has points (1, 4), (1, 2), (5, 3). Triangle B prime C prime D prime

Svet_ta [9481]

The transformation sequence that maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis combined with a translation of 6 units in the x direction and -5 units in the y direction.

Step-by-step explanation:

Let's break down the reflection across the y-axis, horizontal translation, and vertical translation:

1. For point (x, y), reflecting it across the y-axis gives the point (-x, y).

2. Translating point (x, y) h units to the right results in (x + h, y), and h units to the left results in (x - h, y).

3. If point (x, y) is moved k units up, it becomes (x, y + k), and if moved k units down, it is (x, y - k).

∵ The vertices of triangle BCD are (1, 4), (1, 2), (5, 3).

∵ The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3).

∵ The x-coordinates of ΔB'C'D' have the same absolute value as those of ΔBCD but with opposite signs, indicating that ΔB'C'D' results from reflecting ΔBCD across the y-axis.

∵ The vertices of triangle B'C'D' are (-1, 4), (-1, 2), (-5, 3).

∵ The vertices of triangle B''C''D'' are (5, -1), (5, -3), (1, -2).

∵ The reflected x-coordinate -1 becomes +5, and -5 becomes +1,

thus the x-coordinates of triangle B'C'D' are increased by 6.

∵ The images of 4, 2, and 3 yield -1, -3, and -2 respectively,

hence subtracting 5 from the y-coordinates of triangle B'C'D' leads us to ΔB"C"D" through a translation of 6 units right and 5 units down ⇒ (x + 6, y - 5).

The transformation sequence that maps ΔBCD to ΔB"C"D" is:

Reflection across the y-axis combined with a translation of 6 units in the x direction and -5 units in the y direction.

Learn more:

You can explore more about reflection at

3 0

23 days ago

Read 2 more answers