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aev
1 month ago
7

Which phrase represents the algebraic expression StartFraction 3 p + 6 Over 7 p minus 9 End Fraction? the sum of six times a num

ber and three, multiplied by the difference of nine times the number and seven the sum of six times a number and three, divided by the difference of nine times the number and seven the sum of three times a number and six, multiplied by the difference of seven times the number and nine the sum of three times a number and six, divided by the difference of seven times the number and nine
Mathematics
2 answers:
lawyer [12.5K]1 month ago
7 0

Answer:

The expression representing the sum of three times a number and six, over the difference of seven times that number and nine

Step-by-step explanation:

we have

Let

p  -----> the variable

we recognize that

In the numerator, (3p+6)

The phrase that corresponds to this algebraic representation is "The sum of three times a number and six"

The denominator is (7p-9)

The phrase that corresponds to this algebraic representation is "The difference of seven times the number and nine"

therefore

The phrase that represents this problem is "The sum of three times a number and six, divided by the difference of seven times the number and nine"

[[TAG_61]][[TAG_62]]
AnnZ [12.3K]1 month ago
6 0

Answer:

The expression representing the sum of three times a number and six, over the difference of seven times that number and nine

Step-by-step explanation:

we have

\frac{3p+6}{7p-9}

Let

p  -----> the variable

we understand that

In the numerator we have (3p+6)

The statement that corresponds to this algebraic representation is "The sum of three times a number plus six"

The denominator is (7p-9)

The statement that corresponds to this algebraic representation is "The difference of seven times the number and nine"

therefore

The statement that represents this problem is "The sum of three times a number and six, divided by the difference of seven times the number and nine"

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Answer:

Let the train's speed be denoted as x km/h.

Scenario 1:

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Time = Distance divided by Speed

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Scenario 2:

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Speed = (x + 4) km/h

Time = 288/(x + 4) hours

As 288/x is greater than 288/(x + 4)

288/x - 288/(x + 4) = 1

288[1/x - 1/(x + 4)] = 1

[x + 4 - x] / [x(x + 4)] = 1/288

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x + 36 = 0, x - 32 = 0

x = -36, x = 32

x = -36 is not valid as speed cannot be negative.

Conclusively, the train's speed = 32 km/h

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