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Galina-37
1 month ago
9

Collete mapped her vegetable garden on the graph below. Each unit represents 1 foot.

Mathematics
2 answers:
Inessa [12.5K]1 month ago
6 0

Response: I'm not entirely sure.

Explanation step-by-step:

zzz [12.3K]1 month ago
5 0

Answer:

(-4,-1) and (-4,7)

Step-by-step explanation:

When Collete planted the lettuce, the coordinates for those points share either the same vertical or horizontal coordinate. An essential detail is that between these points, there should be 8 units of distance, reflecting the length of an 8-foot row.

Only the initial option satisfies this condition to accurately represent the layout of plants spaced 8 feet apart.

Consequently, the answer is (-4,-1) and (-4,7)

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According to the rule of 72, if Arielle invests $100, $200, and $2000 into three separate accounts with the same interest rate,
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The rule of 72 provides a rough estimate for how long it takes for an investment to double, solely based on the interest rate. Therefore, the initial deposit does not influence this estimate. Each of the three accounts will take an equal time to double.

As long as all accounts are opened on the same day with identical interest rates and compounding periods, they will double simultaneously, whether calculated via the rule of 72 or through precise timing.
5 0
29 days ago
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What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
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Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

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1 month ago
In a circle, an arc 60 centimeters long subtends an angle of 5 radians. What is the radius of the circle?
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Got it!
There are 2π radians in a complete circle.

Now, let's calculate the circumference.
5/2π = 60/circumference.
Next, solve for the circumference.
By multiplying both sides by 2π, we have: 5 * circumference = 120π.
Now divide both sides by 5, and we find: circumference = 24π.

Using the formula c = 2πr,
we set 24π = 2πr.
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