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dolphi86
1 month ago
7

A bag contains chips of which 27.5 percent are blue. A random sample of 5 chips will be selected one at a time and with replacem

ent. What are the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5 ?
Mathematics
1 answer:
lawyer [12.5K]1 month ago
6 0

Answer:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=0.1997

Step-by-step explanation:

It is known that the mean and standard deviation of the sampling distribution of the sample proportion(\hat{p}) are represented as follows:-

\mu _{\hat{p}}=p\\\\ \sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}

, where p= Population proportion and n = sample size.

Let p denote the proportion of blue chips.

According to the information provided, we have

p= 0.275

n= 5

Thus, the mean and standard deviation of the sampling distribution of the sample proportion of blue chips for samples of size 5 will be:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=\sqrt{\dfrac{ 0.275(1- 0.275)}{5}}\\\\=0.19968725547\approx0.1997

Therefore, you will have the mean and standard deviation for the sample proportion of blue chips for samples of size 5:

\mu _{\hat{p}}= 0.275\\\\ \sigma_{\hat{p}}=0.1997

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