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Elis
6 days ago
7

Miranda bought a square frame that has an area of 30 square inches what is the approximate side lenght of the frame

Mathematics
2 answers:
Leona [9.2K]6 days ago
4 0
The side length of the square frame is approximately 5.5 inches. To break it down stepwise, the area of the square frame that Miranda purchased equals 30 square inches. The question asks for the side length of the frame. Given that the area of the square is 30 square inches, we arrive at a side length of about 5.4772 inches.
babunello [8.4K]6 days ago
3 0
The area of a square is calculated by squaring the side length (A = s²). Consequently, 30 = s². Taking the square root gives us s = √30. A calculator shows that √30 is approximately 5.48, or through estimation, we can see that √25 < √30 < √36, suggesting that √30 falls between 5 and 6.
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A soccer ball is kicked upward from a hill and then falls to the ground. The height, in feet, of the ball after t sec is modeled
Zina [9157]

Answer: The ball starts at a height of 12 feet.

Step-by-step explanation:

The height(h) of the ball, measured in feet, after t seconds is modeled by the function h(t)=-16t^2+26t+12.

As height corresponds to time, we can determine that the ball's initial elevation occurs when:

t=0

To ascertain the starting height, substitute t=0 into the equation:

h(0)=-16(0)^2+26(0)+12\\\\h(0)=0+0+12\\\\h(0)=12

Thus, the ball's initial height is 12 feet.

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20 days ago
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If f(x) and f–1(x) are inverse functions of each other and f(x)=2x+5, what is f–1(8)?
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To determine the inverse of f(x)=2x+5, first express it without using f(x). Set y = 2x + 5, then exchange x and y and solve for y. Subtract 5 from both sides to get x - 5 = 2y, and divide through by 2 to find y = (x-5)/2. Therefore, f-1(x) is (x-5)/2. To find f-1(8), substitute 8 for x, resulting in (8-5)/2 = 3/2.
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3 days ago
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Point T is the midpoint of RS, W is the midpoint of RT, and Z is the midpoint of WS. If the length of TZ is x, find the lengths
PIT_PIT [9101]

Let RS be denoted as y.

Given that T is the midpoint of RS, this results in RT = TS = \frac{y}{2}

And W acting as the midpoint of RT, leads to

thus RW = WT = \frac{\frac{y}{2} }{2} = \frac{y}{4}

Given that Z is the midpoint of WS.

Meaning WZ = ZS = \frac{WS}{2} = \frac{WT+TS}{2} = \frac{(\frac{y}{4} +\frac{y}{2} )}{2} =\frac{3y}{8}

Consequently, TZ = TS - ZS = \frac{y}{2} -\frac{3y}{8} = \frac{4y-3y}{8} = \frac{y}{8}

However, TZ is defined as x.

Thus, \frac{y}{8} = x

y = 8x = RS.

A) Length of RW = \frac{y}{4} = \frac{8x}{4} = 2x

B) Length of WZ = \frac{3y}{8} =\frac{3*8x}{8} = 3x

C) Length of RS = y = 8x

D) Length of ZS = WZ = 3x.

An image is provided for clarification.

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3 days ago
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8 days ago
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Svet_ta [9486]

Answer: A total descent of 8260 feet occurred for all four balloons.

Step-by-step explanation:

Based on the information provided:

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Thus, the overall change in altitude for all four balloons can be calculated as:

295\times 7\times 4\\\\=8260\ feet

Thus, a total descent of 8260 feet was experienced by the four balloons.

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17 days ago
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