The table shows the estimated number of lines of code written by computer programmers per hour when x people are working.

Response:

Null hypothesis = H₀ = σ₁² ≤ σ₂²

Alternative hypothesis = Ha = σ₁² > σ₂²

Calculated statistic = 1.9

p-value = 0.206

Given that the p-value exceeds α, we do not reject the null hypothesis.

Thus, we conclude that night shift workers do not exhibit higher variability in their output levels compared to day workers.

Step-by-step elaboration:

Let σ₁² represent the variance for night shift workers

Let σ₂² represent the variance for day shift workers

State the null and alternative hypotheses:

The null hypothesis suggests that the variance of night shift workers does not exceed that of day shift workers.

Null hypothesis = H₀ = σ₁² ≤ σ₂²

The alternative hypothesis posits that the variance for night shift workers surpasses that of day shift workers.

Alternative hypothesis = Ha = σ₁² > σ₂²

Calculated statistic:

The test statistic, or F-value, is derived using

Test statistic = Larger sample variance/Smaller sample variance

The larger sample variance is σ₁² = 38

The smaller sample variance is σ₂² = 20

Test statistic = σ₁²/σ₂²

Test statistic = 38/20

Calculated statistic = 1.9

p-value:

The corresponding degrees of freedom for night shift workers is[1]

df₁ = n - 1

df₁ = 9 - 1

df₁ = 8

The corresponding degrees of freedom for day shift workers is[1]

df₂ = n - 1

df₂ = 8 - 1

df₂ = 7

We can obtain the p-value using the F-table or Excel.

To determine the p-value in Excel, we use

p-value = FDIST(F-value, df₁, df₂)

p-value = FDIST(1.9, 8, 7)

p-value = 0.206

Conclusion:

p-value > α    

0.206 > 0.05   ( α = 0.05)As the

p-value is larger than α, we do not reject the null hypothesis with a confidence level of 95%

[[TAG_101]]This leads us to conclude that night shift workers do not demonstrate more variability in their output levels in comparison to day workers.[[TAG_102]]

Response:

Step-by-step explanation:

To calculate 5% of our number, we start by multiplying by 0.05

Next, by adding and subtracting this 5% from our original number, we can find the minimum and maximum possible values of our final answer in the specified range.

We can ascertain that fits within the acceptable range, as:

Therefore, our final answer will be:

Because

1 USD = 113.83 Japanese Yen

To convert 100 USD: 100 × 113.83 Japanese Yen

Therefore 100 USD = 11,383.00 Japanese Yen

Answer:

Step-by-step explanation:

Let the number of cans collected by Shane be x.

Thus, the number of cans collected by Abha is x + 178.

Given that a minimum of 2000 cans is required to be collected.

Therefore, we have the inequality,[ [TAG_19]]

Total cans by Shane + Total cans by Abha ≥ 2000.

That is,

Thus, the necessary inequality is .

Answer:

-14x is different from 12x², thus they cannot be combined.

To avoid this mistake, ensure that similar terms are properly aligned.

Step-by-step explanation: