Answer:
2.5 hours
Step-by-step explanation:
Distance equals speed multiplied by time. For constant distance, time varies inversely with speed. When traveling at 60/50 = 6/5 times the original speed, the return journey takes 5/6 of the initial duration:
(5/6)(3 hours) = 2.5 hours... return trip duration
Answer:
There is a probability of 24.51% that the weight of a bag exceeds the maximum permitted weight of 50 pounds.
Step-by-step explanation:
Problems dealing with normally distributed samples can be addressed using the z-score formula.
For a set with the mean
and a standard deviation
, the z-score for a measure X is calculated by

Once the Z-score is determined, we consult the z-score table to find the related p-value for this score. The p-value signifies the likelihood that the measured value is less than X. Since all probabilities total 1, calculating 1 minus the p-value gives us the probability that the measure exceeds X.
For this case
Imagine the weights of passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, thus 
What probability exists that a bag’s weight will surpass the maximum allowable of 50 pounds?
That translates to 
Thus



has a p-value of 0.7549.
<pthis indicates="" that="" src="https://tex.z-dn.net/?f=P%28X%20%5Cleq%2050%29%20%3D%200.7549" id="TexFormula10" title="P(X \leq 50) = 0.7549" alt="P(X \leq 50) = 0.7549" align="absmiddle" class="latex-formula">.
Additionally, we have that


There is a probability of 24.51% that the weight of a bag will exceed the maximum allowable weight of 50 pounds.
</pthis>
Answer:
16 years
Step-by-step explanation:
Let x represent the count of years. The suburb population increases at a rate of 5000 annually, which can be formulated as:
320000 + 5000x
The city population decreases at a rate of 14000 per year, represented as:
624000 - 14000x
The point in time when both the suburb and city populations will match can be derived from:
320000 + 5000x = 624000 - 14000x
14000x + 5000x = 624000 - 320000
19000x = 304000
x = 304000 / 19000
x = 16
In 16 years, the populations of both the suburb and the city will be equivalent
B. f(x) ≤ 0 over the interval [0, 2]. D. f(x) > 0 over the interval (–2, 0). E. f(x) ≥ 0 over the interval [2, ).