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23 days ago

The lines below are perpendicular. If the slope of the green line is ą, what is

1 answer:

6 0

See below If I remember correctly, when two slopes are perpendicular, one should be the negative reciprocal of the other, so I believe your answer needs to be B. -\frac{2}{3} Hope this helps

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Your job is to sort and sack marbles for sale. A bag contains 44 marbles, some red and some green. If there are 11 red marbles,

AnnZ [12381]

Response:

The correct choice is option C

The proportion of green marbles to red marbles is 3: 1

Step-by-step breakdown:

According to the problem statement:

A bag holds 44 marbles, comprising both red and green ones.

⇒Total marbles = 44

If it includes 11 red marbles.

Then;

Green marbles = Total marbles - red marbles.

By substituting the values provided,

Green marbles = 44 - 11 = 33

We are tasked with determining the ratio of green marbles to red marbles.

$\frac{\text{Green marbles}}{\text{Red marbles}} = \frac{33}{11} = \frac{3}{1} = 3: 1$

Consequently, the ratio of green to red marbles is 3: 1

8 0

22 days ago

What are three different ways to make the number 15,638 with only hundreds, tens, and ones?

zzz [12365]

I think it’s 156 hundreds, 3 tens, and 8 ones.

3 0

2 months ago

Read 2 more answers

Which expression is equivalent to StartFraction 3 x Superscript negative 6 Baseline y Superscript negative 3 Baseline Over 15 x

zzz [12365]

Answer:

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

Step-by-step explanation:

In order to simplify the expression $\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }$ where x ≠ 0, y ≠ 0, we must work through the given expression.

$\frac{3x^{-6}y^{-3} }{15x^{2}y^{10} }\\= \frac{3}{15} x^{-6-2}y^{-3-10}\\ = \frac{3}{15}x^{-8}y^{-13} \\ =\frac{1}{5}x^{-8}y^{-13} \\$

The appropriate expression is 1 Over 5 x Superscript minus 8 Baseline y Superscript minus 13 Baseline EndFraction

6 0

1 month ago

*TAXES MULTIPLE CHOICE* Zurab works for a salary of $1,986 per month. He has federal income tax withheld at the rate of 15 perce

zzz [12365]

To find the answer, subtract the total percentage of 24.65% and $48 from 1986, resulting in the final value.

8 0

2 months ago

Read 2 more answers

Mike runs for the president of the student government and is interested to know whether the proportion of the student body in fa

zzz [12365]

Answer:

We conclude that less than or equal to 50% of the student body supports him significantly.

Step-by-step explanation:

Mike, while campaigning for the student government presidency, is keen to determine if more than 50% of the student body supports him.

A random sample of 100 students was surveyed, with 55 expressing support for Mike.

Let p = the proportion of students backing Mike.

Thus, Null Hypothesis, $H_0$ : p $\leq$ 50% {indicating that the proportion of supporters among the student body is significantly less than or equal to 50%}

Alternate Hypothesis, $H_A$ : p > 50% {indicating that the proportion of supporters among the student body is significantly more than 50%}

The test statistics to be utilized here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = the sampled proportion in favor of Mike = $\frac{55}{100}$ = 0.55

n = number of sampled students = 100

Therefore, test statistics = $\frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }$

= 1.01

The z test statistic is 1.01.

At a significance level of 0.05, the z table provides a critical value of 1.645 for a right-tailed test.

Given that our test statistic falls below the critical value of z (1.01 < 1.645), we lack sufficient evidence to reject the null hypothesis as it remains outside the rejection region, leading to failure to reject our null hypothesis.

As a result, we conclude that less than or equal to 50% of the student body is in favor of him or the proportion supporting Mike is not significantly greater than 50%.

4 0

1 month ago