50 11th graders were asked to choose which of 6 options the school’s color should be. The table below shows the number of studen

Answer: -3/4

Step-by-step clarification:

We start with

Next, we can factor out the term on the right side

Now, we will substitute back

resulting in

So,

.............Response

Answer:

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

Next, differentiate with respect to 't'

By factoring out i, j, and k terms, we arrive at:

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Multiplication of 2x^2 – 3xy + y^2 and 2x – 4y

Multiplication refers to the product

(2x^2 – 3xy + y^2) (2x – 4y)

Expand the brackets

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Combine like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The result is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3