First, we need to identify the integers between 301 and 400 that are divisible by 4. The initial number is 304, which is the first multiple of 4 in that range. The sequence formed is 304, 308, 312,...,400, creating an arithmetic progression (AP). To determine how many such integers exist, we utilize the AP formula.
The number 55,220 has two 5s and two 2s. The 5s appear in the ten-thousands and thousands places, representing 50,000 and 5,000 respectively. The 2s occupy the hundreds and tens positions, corresponding to 200 and 20. In total, the 5s sum to 55,000, while the 2s add up to 220.
Answer:
Step-by-step explanation:
105 divided by 5 equals 21
21m=b
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The number of layers is calculated as 2^7 = 128. The overall thickness is then 128 multiplied by 0.1, resulting in 12.8 mm. I hope this information is useful.
1,107 cc
The scanning consists of 10 intervals:
[0,1.5), [1.5,3), [3,4.5), [4.5,6), [6,7.5), [7.5,9), [9,10.5), [10.5,12), [12,13.5), [13.5,15)
To estimate the volume using the Midpoint Rule, n should be set to 10.
Given that we will use n=5, we will split the range [0,15] into five intervals of lengths 3 each:
[0,3], [3,6], [6,9], [9,12], [12,15] and calculate their midpoints:
1.5, 4.5, 7.5, 10.5, and 13.5.
Next, we will determine the volume V from the five cylinders, where each has a height h=3 and the base area A corresponds to the calculated midpoints' intervals:
Cylinder 1
Midpoint=1.5, corresponding to the 2nd interval
A = 18, V= height * area of the base = 18*3 = 54 cc
Cylinder 2
Midpoint=4.5, corresponding to the 4th interval
A = 78, V= height * area of the base = 78*3 = 234 cc
Cylinder 3
Midpoint=7.5, corresponding to the 6th interval
A = 106, V= height * area of the base = 106*3 = 318 cc
Cylinder 4
Midpoint=10.5, corresponding to the 8th interval
A = 129, V= height * area of the base = 129*3 = 387 cc
Cylinder 5
Midpoint=13.5, corresponding to the 10th interval
A = 38, V= height * area of the base = 38*3 = 114 cc
Thus, the estimated volume is
54 + 234 + 318 + 387 + 114 = 1,107
