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ioda
3 months ago
12

For every 10 yards on a football field, there is a boldly marked line labeled with the amount of yards. Each of those lines is p

erpendicular to both sidelines. What can be said about the relationship of the sidelines? Justify your answer.
a. The sidelines are perpendicular to each other by the definition of the Transitive Property.

b. The sidelines are parallel by the Same-Side Interior Angles Theorem.

c. The sidelines are perpendicular by the Perpendicular Transversal Theorem

d. The sidelines are parallel because they are perpendicular to the same line.
Mathematics
2 answers:
zzz [12.3K]3 months ago
4 0

Response:

D. The sidelines are parallel because they are perpendicular to a common line.

Justification:

According to the perpendicular transversal theorem, when a line is perpendicular to one of two parallel lines, it is also perpendicular to the other line. Furthermore, the converse of the theorem states that if two lines are perpendicular to the same line, they must be parallel. Therefore, the sidelines are indeed parallel and also perpendicular to this single line.

babunello [11.8K]3 months ago
3 0

The right answer is:

D) The sidelines are parallel since they are perpendicular to a shared line.

Justification:

Each of the sidelines is perpendicular to every 10-yard line. This indicates that the angle formed between the sideline and each 10-yard line is equivalent. Because these angles are consistent, the distance between the sidelines and the 10-yard lines remains constant. Hence, this consistent distance confirms that the sidelines are parallel.

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2 months ago
What value is equivalent to 2 × 3 + 4 − 62?<br> A) -26 <br> B) -22 <br> C) -2 <br> D) 10
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Hello from MrBillDoesMath!

Answer:

-52. None of the alternatives presented is accurate

Discussion:

Based on standard mathematical operations, none of the given solutions is correct. The calculation results in

2*3 + 4- 62 =                => * before + and -

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6 0
2 months ago
Read 2 more answers
On a baseball field, the pitcher’s mound is 60.5 feet from home plate. During practice, a batter hits a ball 195 feet at an angl
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For this scenario, we can visualize that all points form a triangle. The three vertices are at the pitcher's mound, home plate, and the location where the outfielder catches the ball. We know two sides of the triangle and the angle that lies between these two sides.

<span>Using the cosine law, we can find the unknown third side. The formula to apply is:</span>

c^2 = a^2 + b^2 - 2ab cos θ

Where:

a = 60.5 ft

b = 195 ft

θ = 32°

Substituting the provided values results in:

c^2 = (60.5)^2 + (195)^2 - 2(60.5)(195) cos(32)

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c^2 = 21,675.56

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8 0
3 months ago
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Answer:

  • The mean will decrease, while the median remains unchanged.

Explanation:

Using asterisks instead of dots, the plot described is as follows:

Minutes spent by Sarah getting ready for school, rounded to the nearest five minutes:

                                                               *                *

                                      *       *                *       *       *

                              *       *       *                *       *       *

5    10   15   20    25    30    35    40    45    50    55    60

<pwhen the="">new point, 15 minutes, is added to the plot, it becomes:

                                                               *                *

                                      *       *                *       *       *

              *              *       *       *                *       *       *

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The mean will decrease:

The mean is expected to decrease as including a lower value will lower the overall mean.

The calculation is:

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The median will remain unchanged:

Initially, the first graph contains 13 dots, making the median the value at the seventh dot, which is 45.

In the second graph, there are 14 dots, thus the median is the average of the seventh and eighth positions, both of which are 45, resulting in an overall median of 45.

Therefore, the mean will decrease while the median stays the same.

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